The following figure shows \triangle ABC△ABCtriangle, A, B, C with side lengths to the nearest tenth. Triangle ABC. Side AC meas
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Alright, lets get started.
We could use sine law to find the remaining angle.
Plugging the value of sin 64
Cross multiplying
sin S = 0.8189
Taking inverse on both side
S = 55° : Answer
Hope it will help :)
By definition, if two lines share the same gradient, they are said to be parallel. So, we know for this equation, it must have a gradient of 1/2.
Now, since the point (-6, 4) passes through the line, we know it must satisfy the equation. Since we have a gradient/slope and a point, we can use the point-gradient form:
, where 
represents the points being passed through.
Now, since the point (-6, 4) passes through the line, we know it must satisfy the equation. Since we have a gradient/slope and a point, we can use the point-gradient form: