Use the drop-down menus to label the points on the number line.

A school sing games played 160 games and won 65 percent of them how many games did the team win?

jonny [76]

The team won 104 games
160 * 0.65 = 104

8 0

3 years ago

we need to check to see if 27 to the second power + 45 to the second power equals 36 to the second power is a true statement the

Yuri [45]

Answer:

Thx for the points

Step-by-step explanation:

3 0

3 years ago

A supermarket has a length of 150 feet.the area of the supermarket is 1,350 feet squared.what is the width of the supermarket

Amiraneli [1.4K]

Answer:

1,500

Step-by-step explanation:

8 0

3 years ago

The radius of the circle on a basketball court is 6 feet. What are the approximate circumference and area of the circle?

AlexFokin [52]

Circumference formula - 2pi(r)
area formula - pi(r)^2
in both of the formulas r is the radius so

to find circumstance: 2(pi)(6) = 25.68 feet

to find area: pi(6)^2 = 113.04 feet

4 0

2 years ago

Suppose a local manufacturing company claims their production line has a variance of less than 9.0. A quality control engineer d

Alexxx [7]

Answer:

$\chi^2 =\frac{35-1}{9} 2.12^2 =16.979$

$p_v =P(\chi^2$

If we compare the p value and the significance level provided we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

Step-by-step explanation:

Notation and previous concepts

A chi-square test is "used to test if the variance of a population is equal to a specified value. This test can be either a two-sided test or a one-sided test. The two-sided version tests against the alternative that the true variance is either less than or greater than the specified value"

$n=35$ represent the sample size

$\alpha=0.01$ represent the confidence level

$s =2.12$ represent the sample deviation obtained

$\sigma_0 =3$ represent the value that we want to test

Null and alternative hypothesis

On this case we want to check if the population variance specification is lower than 9 and the deviation lower than 3, so the system of hypothesis would be:

Null Hypothesis: $\sigma^2 \geq 9$

Alternative hypothesis: $\sigma^2$

Calculate the statistic

For this test we can use the following statistic:

$\chi^2 =\frac{n-1}{\sigma^2_0} s^2$

And this statistic is distributed chi square with n-1 degrees of freedom. We have eveything to replace.

$\chi^2 =\frac{35-1}{9} 2.12^2 =16.979$

Calculate the p value

In order to calculate the p value we need to have in count the degrees of freedom , on this case df= n-1= 35-1=34. And since is a left tailed test the p value would be given by:

$p_v =P(\chi^2$

In order to find the p value we can use the following code in excel:

"=CHISQ.DIST(16.979,34,TRUE)"

Conclusion

If we compare the p value and the significance level provided we see that $p_v$ so on this case we have enough evidence in order to reject the null hypothesis at the significance level provided. And that means that the population variance is significantly lower than 9

6 0

3 years ago