<em>Answer:</em>
<em>720 %</em>
<em>Step-by-step explanation:</em>
<em>Hi there ! </em>
<em>$ 5 ............. 100%</em>
<em>$ 36 .................x%</em>
<em>x = 36×100/5</em>
<em>= 3600/5</em>
<em>= 720 %</em>
<em>Good luck !</em>
Answer:
Probability of obtaining no more than two defective tubes = 0.816
Step-by-step explanation:
The Probability of obtaining no more than two defective tubes in a randomly selected sample of 15 tubes is obtained using the binomial distribution formula: nCr × p^r × q^(n -r).
Where n is number of samples;
r is maximum number of defective tubes, r ≤ 2;
p is probability of defective tubes = 10% or 0.1
q is probability of non-defective tubes, q = 1 - p
Further explanations and calculations are given in the attachment below:
Answer:
i). 
ii).
Step-by-step explanation:
Given in the question-
Saving rate is s(t)= 3000(t+2)
We know that savings in the 1st year can be calculated as

![3000\left [ \frac{t^{2}}{2}+2t \right ]_0^1](https://tex.z-dn.net/?f=3000%5Cleft%20%5B%20%5Cfrac%7Bt%5E%7B2%7D%7D%7B2%7D%2B2t%20%5Cright%20%5D_0%5E1)
![3000\left [ \frac{1}{2}+2 \right ]](https://tex.z-dn.net/?f=3000%5Cleft%20%5B%20%5Cfrac%7B1%7D%7B2%7D%2B2%20%5Cright%20%5D)
= 
So savings in the first 5 years can be calculated as

![3000\left [ \frac{t^{2}}{2}+2t \right ]_0^5](https://tex.z-dn.net/?f=3000%5Cleft%20%5B%20%5Cfrac%7Bt%5E%7B2%7D%7D%7B2%7D%2B2t%20%5Cright%20%5D_0%5E5)
![3000\left [ \frac{25}{2}+5 \right ]](https://tex.z-dn.net/?f=3000%5Cleft%20%5B%20%5Cfrac%7B25%7D%7B2%7D%2B5%20%5Cright%20%5D)
= 