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Levart [38]
3 years ago
12

Can I please get some help with this problem.

Mathematics
1 answer:
ladessa [460]3 years ago
4 0

Answer:

Area of fig. = 211.142 Unit²

<u>After</u><u> </u><u>rou</u><u>nding</u><u> </u><u>to</u><u> </u><u>the</u><u> </u><u>nea</u><u>rest</u><u> </u><u>tenths</u><u> </u><u>place</u><u> </u><u>=</u><u> </u><u>2</u><u>1</u><u>1</u><u>.</u><u>1</u><u> </u><u>unit²</u>

Step-by-step explanation:

[ Refer to the attached file ]

  • Fig. is already divided into three parts
  • in which two parts are same , they are semicircle!!

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Does the point (0,4) make either equations y=-2x and y=x+3 true? Explain.
Nikolay [14]

Answer:

Neither

Step-by-step explanation:

To verify, we substitute the values in the equations:

y = -2x\\y = -2 \times 0\\y = 0

however, the value should be 4. Hence this equation does not satisfy the co-ordinate.

y = x+3\\y= 0+3\\y = 3

however, the value should be 4. Hence this equation does not satisfy the co-ordinate.

5 0
3 years ago
Solve the inequality. Graph the solution set, and write it using interval notation. |5x+4|less than or equal to 10
aniked [119]

we have the inequality

\lvert5x+4\rvert\leq10

step 1

Find out the first solution (positive case)

\begin{gathered} +(5x+4)\leq10 \\ 5x\leq10-4 \\ 5x\leq6 \\ x\leq\frac{6}{5} \\ x\leq1.20 \end{gathered}

The first solution is all real numbers less than or equal to 1.20

Interval (-infinite,1.20]

step 2

Find out the second solution (negative case)

-(5x+4)\leq10

Multiply by -1 both sides

\begin{gathered} (5x+4)\ge-10 \\ 5x\ge-10-4 \\ 5x\ge-14 \\ x\ge-\frac{14}{5} \\ x\ge-2.8 \end{gathered}

The second solution is all real numbers greater than or equal to -2.8

the interval [-2.8, infinite)

step 3

Find out the solution to the given inequality

The solution is

[-2.8, infinite) ∩ (-infinite,1.20]=[-2.8,1.20]

the solution is the interval [-2.8,1.20]

see the attached figure to better understand the problem

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Answer:

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Step-by-step explanation:

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