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hichkok12 [17]
3 years ago
9

8. Between which two consecutive integers does the radical √77 lie? __< √77 <__

Mathematics
2 answers:
Ugo [173]3 years ago
5 0

Answer:

√77 - 8 and 9 I'm pretty sure!! pls I'm sorry if it's wrong

Katarina [22]3 years ago
3 0

Answer:

i dont know

Step-by-step explanation:

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Write the equation of the line that passes through (2,7) and (0, 1).
dsp73

Answer:

y=3x+1

Step-by-step explanation:

First, you need to find the slope. With the two points you can find the slope by subtracting one point from the other. This gives you a slope of 3. You could plot this on a graph to get the +1, or you can just look at these two points. (0,1) just gives it to you because this point is on the line.

8 0
3 years ago
Please help me <br>will mark brainliest​
MAVERICK [17]

Answer:

4

-20

-12

Step-by-step explanation:

g(4)

= 4(4)-12

= 16-12

= 4

g(-2)

=4(-2)-12

=-8-12

=-20

g(0)

=4(0)-12

=0-12

=-12

6 0
4 years ago
Bethany can mow her lamily's lawn in 4 hours. Her brother coin can mow the lawn into hoursWhich equation can ve
DaniilM [7]

Answer:

1/x = 1/4 + 1/3

Step-by-step explanation:

In 4 hours Bethany did the whole fraction 1 of the house.

In 1 hour he would do 1/4 of it.

In 3 hours Colin did the whole fraction 1 of the house.

In 1 hour he would do 1/3 of it.

In 1 hour they would both do (1/4 + 1/3)

If it takes both of them x hours to finish 1 whole fraction of the house.

In 1 hour they will both do 1/x

That means that:

1/x = 1/4 + 1/3

That is the equation. x can be solved for.

3 0
3 years ago
A simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute
GREYUIT [131]

Answer:

(a) Null Hypothesis, H_0 : \sigma = 10 beats per minute  

     Alternate Hypothesis, H_A : \sigma\neq 10 beats per minute  

(b) The value of chi-square test statistics is 35.704.

(c) P-value = 0.4360.

(d) We conclude that the pulse rates of men have a standard deviation equal to 10 beats per minute.

Step-by-step explanation:

We are given that a simple random sample of 36 men from a normally distributed population results in a standard deviation of 10.1 beats per minute.

If the range rule of thumb is applied to that normal​ range, the result is a standard deviation of 10 beats per minute.

Let \sigma = <u><em>population standard deviation for the pulse rates of men</em></u>.

(a) So, Null Hypothesis, H_0 : \sigma = 10 beats per minute      {means that the pulse rates of men have a standard deviation equal to 10 beats per minute}

Alternate Hypothesis, H_A : \sigma\neq 10 beats per minute      {means that the pulse rates of men have a standard deviation different from 10 beats per minute}

The test statistics that will be used here is <u>One-sample chi-square test</u> for standard deviation;

                             T.S.  =  \frac{(n-1)\times s^{2} }{\sigma^{2} }  ~  \chi^{2}__n_-_1  

where, s = sample standard deviation = 10.1 beats per minute

            n = sample of men = 36

So, <u><em>the test statistics</em></u> =  \frac{(36-1)\times 10.1^{2} }{10^{2} }  ~ \chi^{2}__3_5

                                   =  35.70  4

(b) The value of chi-square test statistics is 35.704.

(c) Also, the P-value of the test statistics is given by;

                    P-value = P(\chi^{2}__3_5 > 35.704) = <u>0.4360</u>

(d) Since the P-value of our test statistics is more than the level of significance as 0.4360 > 0.10, so <u><em>we have insufficient evidence to reject our null hypothesis</em></u> as the test statistics will not fall in the rejection region.

Therefore, we conclude that the pulse rates of men have a standard deviation equal to 10 beats per minute.

3 0
4 years ago
Does anyone know what 1+1 is?
hammer [34]

1+1 = 2  that is the answer


6 0
3 years ago
Read 2 more answers
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