A: To find the rate in feet per minute, we can use the information given.
Every two minutes, the submarine dives 300 feet. So

.
In order to confirm that our rate is correct, we can use the second set of information given.

=

.
Since we know that the rate is 150 feet per minute, we can multiply it by any number of minutes and get the answer of how deep the submarine is. We can use a variable x to represent the number of minutes and y to represent the depth in feet.

There's our equation.
B: It would be more reasonable to use an equation with the rate feet per minute because it is more accurate since the time interval isn't too big.
Answer:
35 ft
Step-by-step explanation:
Sorry this took me so long, I am 99% sure it is right though
I hope this helps :)
Answer:
The other solution is 12.
Step-by-step explanation:
Break the solution into groups: (x^2+2x)+(-12x-24)
Factor out the x^2 from the first group to get x(x+2)
Factor out the -12 out of the second group to get -12(x-12)
Here we get (x-12)(x+2)
You can see solutions are -2 and 12.
Answer:
1/8
Step-by-step explanation:
sin²(π/8) − cos⁴(3π/8)
Use power reduction formulas:
1/2 (1 − cos(2×π/8)) − 1/8 (3 + 4 cos(2×3π/8) + cos(4×3π/8))
Simplify:
1/2 (1 − cos(π/4)) − 1/8 (3 + 4 cos(3π/4) + cos(3π/2))
1/2 (1 − √2/2) − 1/8 (3 + 4 (-√2/2) + 0)
1/2 − √2/4 − 1/8 (3 − 2√2)
1/2 − √2/4 − 3/8 +√2/4
1/2 − 3/8
1/8
Answer:
Distance between two points= √(x2-x1)²+(y2-y1)²
D= 15units
Let "k" be the y-coordinate of A
A(-6,k)
B(3,2)
15= √(3--6)²+(2-k)²
Taking square of both sides to eliminate the square root.
15²=(9)²+(2-k)²
225=81+4-4k+k²
k²-4k - 140=0
Using Quadratic Formula to evaluate
k= 14 or k=-10
The Possible coordinates of A are
(-6,14) or (-6,-10)