Initial amount is when no change has happened or when t=0
that iniital amoun tis 1
the growth factor
welll, it grows by 40% each time of previous times
I would say growth factor of 1.4
f(x)=a(b)^t
f(t)=1(1.4)^t
initial amount is 1
grouth factor is 1.4
<span><em>Hope his helps!!!!!!!
</em><em>Ps: Please mark brainliest!!!! I am only a few away from ranking up, it would help a lot, and I will make a shoutout for you!! </em></span>
Answer : p(only z)=0.40 and p(only u)=0.08
Explanation :
We have given that ,
p(u)=0.22,
p(z∪u)=0.62,
p(z)=0.54
By using probability rule of union of 2 events, we have,
p(z)+p(u)-p(z∩u)=p(z∪u)
⇒0.54+0.22-p(z∩u)=0.62
⇒0.76-p(z∩u)=0.62
⇒(-)p(z∩u)=0.62-0.76
⇒(-)p(z∩u)= (-)0.14
⇒p(z∩u)=0.14
Now,
p(only z)=p(z)-p(z∩u)
=0.54-0.14
=0.40
and,
p(only u)=p(u)-p(z∩u)
=0.22-0.14
=0.08
∴ Each probability will be
p(only z)=0.40
p(only u)=0.08

A. Area of given figure = 280 + 77 = 357 cm²
B. length of semicircle = 22 cm
Answer:
Part 1) The algebraic expression is equal to
or 
Part 2) The algebraic expression is equal to 
Step-by-step explanation:
Part 1) we have (n-1) increased by 110%
110%=110/100=1.10
so
The algebraic expression of (n-1) increased by 110% is equal to multiply 1.10 by (n-1)

Distributed

Part 2) we have n^(-1) increased by 110%
110%=110/100=1.10
so
The algebraic expression of n^(-1) increased by 110% is equal to multiply 1.10 by n^(-1)
Remember that

so
