All categories

2 years ago

Broooooooooo help me

Mathematics

2 answers:

MA_775_DIABLO [31]2 years ago

7 0

Answer:

h(5)=20(5)-15

=100-15=85

Olenka [21]2 years ago

4 0

Answer:

$h(x) = 20x - 15 \\ h(5) = 20 \times 5 - 15 \\ = 100 - 15 \\ = 85 \\ hank \: you$

You might be interested in

4x2 = 52

maxonik [38]

Answer:

x=13

x=-13 and 13

hmm I think

8 0

3 years ago

Read 2 more answers

The beverage orders from school cafeteria are shown in the graph. If 760 students purchase a beveragehow many of the students ch

kari74 [83]

according to the graph, 25% chose water, and

$\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{25\% of 760}}{\left( \cfrac{25}{100} \right)760}\implies 190$

5 0

3 years ago

Attila the Hun was a ruler of the Hunnic Empire. The Romans feared him greatly until his death since he made quite a habit of in

Bas_tet [7]

The inequality would be x > 453 because any year after he died would be more than the year he died.
Also, if it helps, I think of inequalities as an alligator's mouth, trying to eat the bigger quantity.
Hope this helps!

8 0

3 years ago

I need help with #11

Troyanec [42]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\

\begin{array}{rllll} 
% left side templates
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}$

$\bf \begin{array}{llll}
% right side info
\bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\qquad if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\end{array}$

$\bf \begin{array}{llll}


\bullet \textit{ vertical shift by }{{ D}}\\
\qquad if\ {{ D}}\textit{ is negative, downwards}\\\\
\qquad if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}
\end{array}$

now, with that template in mind, let's take a peek at this function

$\bf \begin{array}{lllcclll}
y=&2(&1x&-2)^2&-4\\
&\uparrow &\uparrow &\uparrow &\uparrow \\
&A&B&C&D
\end{array}\\\\
-----------------------------\\\\
A\cdot B=2\impliedby \textit{shrunk by a factor of 2, of half-size}\\\\
\cfrac{C}{B}= \cfrac{-2}{1}\implies -2\impliedby \textit{horizontal right shift of 2 units}\\\\
D=-4\impliedby \textit{vertical down shift of 4 units}$

so, the graph of y=2(x-2)²-4, is really the same graph of y=x², BUT, narrower, and moved about horizontally and vertically

8 0

3 years ago

Read 2 more answers

If AC=12, BC=3, find CE<br> 1) 3 square root of 3<br> 2) 6<br> 3) 18

azamat

Answer:

2) 6

Step-by-step explanation:

CE^2 = BC * AC

CE^2 = 3 * 12

CE^2 = 36

CE = 6