Please Help!!!......

krok68 [10]

A parabola, a graph of a quadratic function, cannot have a maximum vertex and a minimum vertex at the same time because of the shape of the graph. A parabola is a u-shaped graph. The vertex of the parabola is the point where the u changes direction; if it was increasing, it starts to decrease, and if it was decreasing, it starts to increase. Since a parabola only changes direction once, there will either be a minimum or a maximum, not both.

7 0

2 years ago

what is an equation of the line perpendicular to y+1=-3(x-5) and passes through (4,-6)? please help quick

Fiesta28 [93]

Step-by-step explanation:

The slope of the given line is -3. Since perpendicular lines have slopes that are negative reciprocals of each other, the slope of the line we need to find is 1/3.

Substituting into point slope form, we get:

y + 6 = ⅓(x+6)

7 0

2 years ago

Read 2 more answers

Anyone good at composite functions??

sammy [17]

$\bf \begin{cases} ~\hfill f(x) = &-3x+4\\ ~\hfill g(x) = &x^2\\ (g \circ f)(0)=&g(~~f(0)~~) \end{cases} \\\\[-0.35em] ~\dotfill\\\\ f(0) = -3(0)+4\implies \boxed{f(0) = 4} \\\\\\ g(~~f(0)~~)\implies g\left( \boxed{4} \right) = (4)^2\implies \stackrel{(g \circ f)(0)}{g(4)} = 16$

6 0

3 years ago

A line in the xy-plane that passes through the coordinate points (3, -6) and (–7, –4) will never intersecta line that is represe

anyanavicka [17]

Answer:

option A

Step-by-step explanation:

given coordinate (3, -6) and (–7, –4)

to find the equation of line

slope of the line passing through both the point will be

$m = \dfrac{y_2-y_1}{x_2-x_1}$

$m = \dfrac{-4+6}{-7-3}$

$m = -\dfrac{2}{10}$

equation of line

( y - y₁ ) = m ( x - x₁ )

$y + 6= -\dfrac{2}{10}(x - 3)$

x + 5 y = -27

line which will not intersect will be parallel to it so option A has same slope as our line equation i.e. -1/5

hence, correct answer is option A

3 0

3 years ago

For the following demand equation compute the elasticity of demand and determine whether the demand is elastic, unitary, or inel

adelina 88 [10]

Answer:

Demand is inelastic at p = 9 and therefore revenue will increase with

an increase in price.

Step-by-step explanation:

Given a demand function that gives q in terms of p, the elasticity of demand is

$E=|\frac{p}{q}\cdot \frac{dq}{dp} |$

If E < 1, we say demand is inelastic. In this case, raising prices increases revenue.
If E > 1, we say demand is elastic. In this case, raising prices decreases revenue.
If E = 1, we say demand is unitary.

We have the following demand equation $D(p)=-\frac{3}{4}p+29$ ; p = 9

Applying the above definition of elasticity of demand we get:

$E(p)=\frac{p}{q}\cdot \frac{dq}{dp}$

where

p = 9
q = $-\frac{3}{4}p+29$
$\frac{dq}{dp}=\frac{d}{dp}(-\frac{3}{4}p+29)$

$\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{d}{dp}\left(\frac{3}{4}p\right)+\frac{d}{dp}\left(29\right)\\\\\frac{d}{dp}\left(-\frac{3}{4}p+29\right)=-\frac{3}{4}$

Substituting the values

$E(9)=\frac{9}{-\frac{3}{4}(9)+29}\cdot -\frac{3}{4}\\\\E(9)=\frac{36}{89}\cdot -\frac{3}{4}\\\\E(9)=-\frac{27}{89}\approx -0.30337$

$|E(9)|=|\frac{27}{89}| < 1$

Demand is inelastic at p = 9 and therefore revenue will increase with an increase in price.

6 0

3 years ago

Please Help!!!......​

Please Help!!!......