Answer:
The probability that a randomly selected carton has a puncture or a smashed corner is 0.143
Step-by-step explanation:
we know that P(A∪B) = P(A) + P(B) - P(A∩B).
since given that P(A) = Probability of getting puncture = 0.08
P(B) = probability of getting smashed corner = 0.07
P(A∩B) = probability of getting both puncture and smashed corner = 0.007
P(A∪B) = probability of getting any of them
so P(A∪B) = 0.08 + 0.07 -0.007 = O.143
The solution to the problem is as follows:
<span>((1+.1784/365)^365) - 1 =.1953=19.53%
</span>
Therefore, best and most correct answer among the choices provided by your question is the fourth choice or letter D. 19.53%
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Answer:
0.037
Step-by-step explanation:
If the hitter makes an out 72% of the time, then the probabilty that he makes hit in 1 at-bat is 
and the probabilty that he doesn't make hit in 1 at-bat is 
The probability that the hitter makes 10 outs in 10 consecutive at-bats, assuming at-bats are independent events is
Answer:
Step-by-step explanation:
The scientific notation:
We have:
