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Diano4ka-milaya [45]
2 years ago
12

7 x 1/5 as a mixed number

Mathematics
2 answers:
iVinArrow [24]2 years ago
7 0

Answer:

It's 15/7

Step-by-step explanation:

ItsJulyCrazy15
2 years ago
Actually, it is 1 2/5.
ItsJulyCrazy152 years ago
0 0

7 x 1/5
= 7/5
= 1 2/5

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Katyanochek1 [597]
Could you please show the question so I can try to answer it
4 0
3 years ago
In a store, a sample of 60 pens was selected from a box of 1,200 pens. Of these 60, 4 pens did not work. About how many pens cou
Lapatulllka [165]
Ok so if 1200 total pens and 60 were taken that's a ratio of 1200/60=20

out of 60pens 4 didn't work, again ratio is 4/60=1/15 so about 1/15 of the pens didn't work. 

so we have 1200pens * 1/15broken ratio = 80 pens or we can say 

20*4=80pens won't work from 20 groups of 60 and 4 out of 60 not working is 20*4=80 not working from total batch of 1200.

hope this helps you some! thank you!!!!!!!!!
3 0
3 years ago
An ant weigh 0.000003 kg. How much would 2 ants weigh, expressed in scientific notation?
Alik [6]
The correct answer is 6*10^-6 ..........................
5 0
3 years ago
In the triangle below, suppose that m/Q = (2x-3)°, m/R= (5x+7)°, and m/S=xº.
o-na [289]

Answer:

Please Attach The Pic so someone can answer.....

Step-by-step explanation:

7 0
2 years ago
8/x-5 - 9/x-4 = 5/x^2-9x+20
adelina 88 [10]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2752942

_______________


Solve the equation:

\mathsf{\dfrac{8}{x-5}-\dfrac{9}{x-4}=\dfrac{5}{x^2-9x+20}\qquad\qquad(x\ne 5~and~x\ne 4)}


Reduce the fractions at the left side so that they have the same denominator:

\mathsf{\dfrac{8(x-4)}{(x-5)(x-4)}-\dfrac{9(x-5)}{(x-4)(x-5)}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-4x-5x+20}-\dfrac{9x-45}{x^2-4x-5x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32}{x^2-9x+20}-\dfrac{9x-45}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}\\\\\\
\mathsf{\dfrac{8x-32-(9x-45)}{x^2-9x+20}=\dfrac{5}{x^2-9x+20}}


Numerators must be equal:

\mathsf{8x-32-(9x-45)=5}\\\\
\mathsf{8x-32-9x+45=5}\\\\
\mathsf{8x-9x=5+32-45}\\\\
\mathsf{-x=-8}\\\\
\mathsf{x=8}\quad\longleftarrow\quad\textsf{this is the solution.}


I hope this helps. =)


Tags:  <em>rational equation fraction solution algebra</em>

7 0
3 years ago
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