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svetlana [45]
3 years ago
11

A stock trading company charges a commission of $10 per trade plus $0.025 per dollar value of stock traded. If your commission i

s $140 , what was the value of the stock you traded?
Mathematics
2 answers:
pickupchik [31]3 years ago
4 0

Answer:

Value of the stock traded was $5200.

Step-by-step explanation:

In this question it is given that trading company charges commission of $10 per trade or transaction plus $.025 per dollar value of stock.We have to calculate the value of stock we traded if total commission (commission on trade value + commission on trade) is $140.

Let the value of stock traded was $x.

Then commission on value of the stock = x×.025

Commission on transaction = $10

Total commission = 140 = ( .025x + 10)

⇒.025x = 140-10 = 130

x = 130÷.025 = $5200

So the value of the stock = $5200

ss7ja [257]3 years ago
4 0

Answer:

$5200  

Step-by-step explanation:

Let C = total commission

and d = dollar value of stock

Then

C = 10 + 0.025d

Let C =140

140 = 10 + 0.025d     Subtract 10 from each side

130 = 0.025d               Divide each side by 0.025

  d = $5200

The value of the stock was $5200.

<em>Check: </em>

140 = 10 + 0.025 × 5200

140 = 10 + 130

140 = 140

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Step-by-step explanation:

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D² = ( 5 )²

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3 years ago
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Seven more than a number, x, is at most 20
Verdich [7]

Answer:

x+7 ≤ 20

Just take it step by step:

seven more than a number is a number plus 7 (x+7)- keep in mind we dont know what the number is so we use x to represent the number.

it then says it's equal to at most 20.

This means that it cant equal anything above 20 since 20 is the max. Therefore, it must be 20 and below that x+7 equals

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≤ -this symbol means less than or equal to

Step-by-step explanation:

3 0
3 years ago
The sum of two numbers is 50 and their difference is 4 what are the two numbers
Deffense [45]

Answer:

27 and 23

Step-by-step explanation:

We can solve this problem as a system of equations. X is the first number and Y is the second number.

The first equation is x+y = 50 and the second equation is x-y=4

Now we solve the system, using elimination method:

x+y=50

x-y=4

2x = 54

x = 54/2

x = 27

And from any of the equations we can find Y

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6 0
3 years ago
One positive number is 14 less than another positive number. If the reciprocal of the smaller number is added to five times the
Kipish [7]

Let's call the two numbers s and l.


Given these variables, we can say: s = l - 14, based on the first sentence in the problem.


Also, remember that the reciprocal of a number is simply 1 divided by the number. Thus, we can say that:

\dfrac{1}{s} + 5\Big( \dfrac{1}{l} \Big) = \dfrac{1}{4}


To solve, we can simply substitute l -14 in for s in the second equation and solve.

\dfrac{1}{l - 14} + \dfrac{5}{l} = \dfrac{1}{4}

  • Set up

\dfrac{l}{l(l - 14)} + \dfrac{5(l - 14)}{l(l - 14)} = \dfrac{1}{4}

  • Get terms on the left side to a common denominator for easier addition

\dfrac{l + 5l - 70}{l(l - 14)} = \dfrac{1}{4}

  • Simplify

4(6l - 70) = l(l - 14)

  • Cross multiplication (\frac{a}{b} = \frac{c}{d} \Rightarrow ad = bc)

24l - 280 = l^2 - 14l

  • Simplify

l^2 - 38l + 280 = 0

  • Subtract 24l - 280 from both sides of the equation

(l - 10)(l - 28) = 0

  • Factor left side of the equation

l = 10, 28

  • Zero Product Property

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s = 10 - 14 = -4,

Since s is not positive in this case, l = 10 is not a solution.


Thus, l = 28 is our only solution. In this case,

s = 28 - 14 = 14,

which means that the smaller number is 14 and the larger number is 28.

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