The probability that the Yankees will lose when they score fewer than 5 runs is 17.16%.
<h3><u>Probability </u></h3>
Given that this season, the probability that the Yankees will win a game is 0.61 and the probability that the Yankees will score 5 or more runs in a game is 0.56, and the probability that the Yankees win and score 5 or more runs is 0.44, to determine what is the probability that the Yankees will lose when they score fewer than 5 runs the following calculation must be made:
- 1 - 0.61 = 0.39
- 1 - 0.56 = 0.44
- 0.39 x 0.44 = X
- 0.1716 = X
Therefore, the probability that the Yankees will lose when they score fewer than 5 runs is 17.16%.
Learn more about probability in brainly.com/question/11234923
#SPJ1
This question is incomplete, in that the Excel File: data07-11.xlsx a. was not provided, but I was able to get the information on the Excel File: data07-11.xlsx a. from google as below:
57 61 86 74 72 73
20 57 80 79 83 74
The image of the Excel File: data07-11.xlsx a. is also attached below.
Answer:
a) Point estimate of sample mean = 68
b) Point estimate of standard deviation (4 decimals) = 17.8122
Step-by-step explanation:
a) Point estimate of sample mean, \bar{x} = ∑Xi / n = (57 + 61 + 85 + 74 + 73 + 72 + 20 + 58 + 81 + 78 + 84 + 73)/12 = 68
b) Point estimate of standard deviation = sqrt ∑ Xi² - n\bar{x}² / n-1)
= sqrt(((57 - 68)^2 + (61 - 68)^2 + (85 - 68)^2 + (74 - 68)^2 + (73 - 68)^2 + (72 - 68)^2 + (20 - 68)^2 + (58 - 68)^2 + (81 - 68)^2 + (78 - 68)^2 + (84 - 68)^2 + (73 - 68)^2)/11) = 17.8122
Answer:
c. (x+3)(x+9)
Step-by-step explanation:
x^2+12x+27
The middle number is 12 and the last number is 27.
We need two numbers that...
Add together to get 12
Multiply together to get 27
Try 3 and 9:
3+9 = 12
3*9 = 27
Fill in the blanks in
(x+_)(x+_)
with 3 and 9 to get...
(x+3)(x+9)
40% helping customers + 13% doing paper work = 53% of his time.
This means 100% - 53% = 47% of his time he is doing other tasks.
So multiplying two rationals is the same as multiplying two such as fraction as when you multiplying two rational numbers produces another rational number.
