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2 years ago

A triangle has side lengths of

Mathematics

1 answer:

alexandr402 [8]2 years ago

6 0

Answer:

P = ( 4y + 6 inches) + ( 8y - B ) inches + ( 5y + 3 ) inches

Step-by-step explanation:

Formula of Perimeter of triangle is = Sum of all sides.

P = A + B + C

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Help please !! thank youu

VLD [36.1K]

Answer:

d = √91 ft = about 9.53 ft

Step-by-step explanation:

use pythagorean theorem which is a²+b²=c²

(the hypotnuse which is opposite side of the right angle is always going to be C in the pythagorean theorem)

a = 3 b = ? c = 10

(3)² + b² = (10)²

9 + b² = 100

subtract 9 from both sides

b² = 91

take the square root of both sides

b = ±√91

so the side d = √91 ft = about 9.53 ft

3 0

2 years ago

Name

Damm [24]

Answer: The correct answer is Tyrell, Yen, Hana....its C

Step-by-step explanation: Hope this helped :}

4 0

2 years ago

A rectangular Corn Hole area at the Recreation Center has a width of 5 feet and a length of 10 feet. If

inysia [295]

Answer:

2 feet

Step-by-step explanation:

Let

x ----> the uniform amount added to each side

we know that

The algebraic expression that represent this situation is

$(5+x)(10+x)=84$

solve for x

Apply distributive property

$50+ 5x+10x+x^2=84\\x^2+15x-34=0$

solve the quadratic c equation

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b\pm\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$x^2+15x-34=0$

$a=1\\b=15\\c=-34$

substitute in the formula

$x=\frac{-15\pm\sqrt{15^{2}-4(1)(-34)}} {2(1)}$

$x=\frac{-15\pm\sqrt{361}} {2}$

$x=\frac{-15\pm19} {2}$

$x=\frac{-15\pm19} {2}=2$

$x=\frac{-15\pm19} {2}=-17$

therefore

The solution is x=2 ft

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3 years ago

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Lorico [155]

The fundamental theorem of calculus tells you

$\displaystyle \frac{d}{dt}\left(\int{\frac{\cos{t}}{t}\,dt}\right)=\frac{\cos(t)}{t}$

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3 B B' A 0 -3 In the image, two circles are centered at A. The circle containing B was dilated to produce the circle containing

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