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3 years ago

I need answer Immediately!!!!!!

Mathematics

1 answer:

Mnenie [13.5K]3 years ago

7 0

Step-by-step explanation:

number of hours = more than 12

above 80= 16

total sat = 33

percentage above 80 = 16 / 33 * 100

= 48.48%

to the nearest whole number = 48%

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The midpoint of AB is M(3,-1).If the coordinates of A are (8,4) what are the coordinates of B

Alchen [17]

Answer:

B(-2,-6)

Step-by-step explanation:

The midpoint of AB is M, then A(8,4), M(3,-1)

So we can find:

$x_{B} =2x_{M} -x_{A}= 2*3-8= -2\\y_{B}= 2y_{M} -y_{A} = 2*(-1)- 4= -6\\$

then B(-2,-6), hope that useful.

6 0

3 years ago

The range of 8,7,12,7,11,10,7,12

allsm [11]

Answer:

a) Median: 9

b) Range: 5

c) Mode: 7

Explanation:

The median is the number in the middle.

First, you put the numbers in order: 7, 7, 7, 8, 10, 11, 12, 12

The middle of this is 8 and 10, so you plus them and divide by to 2, then it gives 9, so the median is 9.

To find the range, you minus the highest number and the lowest number, 12-7=5.

Mode is the most occurring and repetitive number, in this case, 7, because it is written 3 times.

Read more about this on brainly: brainly.com/question/17122811

5 0

2 years ago

Read 2 more answers

Two records and three tapes cost $31. Three records and two tapes cost $29. Find the cost of each record and each tape

Arisa [49]

Answer:

The records cost $5 and the tapes cost $7

Step-by-step explanation:

5 0

3 years ago

PLZ HELPP ASAP :))))))

leva [86]

Answer:

x = 91.5

Step-by-step explanation:

for 30.5 miles travelled gas used is 1 gallon ← unit rate

To calculate distance travelled multiply gas used by 30.5

For 3 gallons used

distance travelled = 3 × 30.5 = 91.5 miles

⇒ x = 91.5

8 0

2 years ago

Compute the differential of surface area for the surface S described by the given parametrization.

AysviL [449]

With $S$ parameterized by

$\vec r(u,v)=\langle e^u\cos v,e^u\sin v,uv\rangle$

the surface element $\mathrm dS$ is

$\mathrm dS=\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|\,\mathrm du\,\mathrm dv$

We have

$\dfrac{\partial\vec r}{\partial u}=\langle e^u\cos v,e^u\sin v,v\rangle$

$\dfrac{\partial\vec r}{\partial v}=\langle -e^u\sin v,e^u\cos v,u\rangle$

with cross product

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle ue^u\sin v-ve^u\cos v,-ve^u\sin v-ue^u\cos v,e^{2u}\cos^2v+e^{2u}\sin^2v\rangle$

$\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}=\langle e^u(u\sin v-v\cos v),-e^u(v\sin v+u\cos v),e^{2u}\rangle$

with magnitude

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=\sqrt{e^{2u}(u\sin v-v\cos v)^2+e^{2u}(v\sin v+u\cos v)^2+e^{4u}}$

$\left\|\dfrac{\partial\vec r}{\partial u}\times\dfrac{\partial\vec r}{\partial v}\right\|=e^u\sqrt{u^2+v^2+e^{2u}}$

So we have

$\mathrm dS=\boxed{e^u\sqrt{u^2+v^2+e^{2u}}\,\mathrm du\,\mathrm dv}$

8 0

3 years ago