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3 years ago

The answers are 2x1/3 , 3x1/3, 5x1/3or 4x1/3

Mathematics

1 answer:

Oxana [17]3 years ago

6 0

Answer:

what is the question? Please ask a question.

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Can someone help with question 3

kirza4 [7]

Answer:

This is what you have to explain:

With 5n, you are multiplying a number and a variable.

With 5 + n, you are adding a number and a variable.

4 0

3 years ago

-2 2/3 divided by 4/3

Vedmedyk [2.9K]

Answer:

-2

Step-by-step explanation:

$Rule(s): a\frac{b}{c} = \frac{a \cdot c + b}{c}, \frac{-a}{b}=-\frac{a}{b}, \frac{\frac{a}{b}}{\frac{c}{d}}=\frac{a\cdot \:d}{b\cdot \:c} \\2\frac{2}{3}=\frac{2\cdot 3+2}{3}\\=\frac{8}{3}\\=\frac{-\frac{8}{3}}{\frac{4}{3}}\\=-\frac{\frac{8}{3}}{\frac{4}{3}}\\=\frac{-8\cdot \:3}{3\cdot \:4}\\= \frac{-24}{12}\\= -2$

8 0

2 years ago

Can you guys pls help me out

34kurt

Answer:

answer C

i think

hope this helps

8 0

3 years ago

Read 2 more answers

How do you multiply fractions by whole numbers?

umka21 [38]

Rewrite the whole number as a fraction. To rewrite a whole number as a fraction, simply place the whole number over 1. ...Multiply the numerators of the two fractions. ...Multiply the denominators of the two fractions. ...Simplify.

4 0

3 years ago

Read 2 more answers

Determine whether or not the vector field is conservative. if it is, find a function f such that f = ∇f. if the vector field is

amm1812

$\dfrac{\partial f}{\partial x}=3y^2z^3\implies f(x,y,z)=3xy^2z^3+g(y,z)$

$\dfrac{\partial f}{\partial y}=6xyz^3+\dfrac{\partial g}{\partial y}=6xyz^3$
$\implies\dfrac{\partial g}{\partial y}=0\implies g(y,z)=h(z)$

$\dfrac{\partial f}{\partial z}=9xy^2z^2+\dfrac{\mathrm dh}{\mathrm dz}=9xy^2z^2$
$\implies\dfrac{\mathrm dh}{\mathrm dz}=0\implies h(z)=C$

$\implies f(x,y,z)=3xy^2z^3+C$

The potential function exists, so $\mathbf f$ is indeed conservative.

7 0

3 years ago