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3 years ago

State if the triangles are similar. If so, how do you know they are similar and complete the similarity statement.

Mathematics

2 answers:

attashe74 [19]3 years ago

7 0

You know there similar from the AA~ because it shows that

malfutka [58]3 years ago

6 0

Answer:

FED ~ MLF

Step-by-step explanation:

∠L = ∠E

∠F = ∠F

Since both angles are congruent, that would mean all angles are congruent.

If all angles are congruent, then the triangles are always similar no matter the length of the sides.

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True or false Controlled experiments can be randomized or nonrandomized

DIA [1.3K]

Answer:

True

Step-by-step explanation:

Using a random chance procedure to assign subjects to treatment or control reduces bias. d. In a blind experiment, the subjects do not know whether they are in the treatment group or control group.

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3 years ago

One less then five times a number is fewer then twenty four

NISA [10]

5n - 1 < 24 is the inequality in question. Add 1 to both sides, obtaining:

5n < 25. Divide both sides by 5, obtaining n < 5 (answer)

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3 years ago

Best explained and correct answer gets brainliest

storchak [24]

The answer is B because they are congruent triangles.

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3 years ago

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What is the average of pi

Oksanka [162]

The average of pi is 3.14 and is an irrational #

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2 years ago

Determine the number of real solutions for each of the given equations. Equation Number of Solutions y = -3x2 + x + 12 y = 2x2 -

rosijanka [135]

Answer:

Step-by-step explanation:

Our equations are

$y = -3x^2 + x + 12\\y = 2x^2 - 6x + 5\\y = x^2 + 7x - 11\\y = -x^2 - 8x - 16\\$

Let us understand the term Discriminant of a quadratic equation and its properties

Discriminant is denoted by D and its formula is

$D=b^2-4ac\\$

Where

a= the coefficient of the $x^{2}$

b= the coefficient of $x$

c = constant term

Properties of D: If D

i) D=0 , One real root

ii) D>0 , Two real roots

iii) D<0 , no real root

Hence in the given quadratic equations , we will find the values of D Discriminant and evaluate our answer accordingly .

Let us start with

$y = -3x^2 + x + 12\\a=-3 , b =1 , c =12\\D=1^2-4*(-3)*(12)\\D=1+144\\D=145\\D>0 \\$

Hence we have two real roots for this equation.

$y = 2x^2 - 6x + 5\\$

$y = 2x^2 - 6x + 5\\a=2,b=-6,c=5\\D=(-6)^2-4*2*5\\D=36-40\\D=-4\\D$

Hence we do not have any real root for this quadratic

$y = x^2 + 7x - 11\\a=1,b=7,-11\\D=7^2-4*1*(-11)\\D=49+44\\D=93\\$

Hence D>0 and thus we have two real roots for this equation.

$y = -x^2 - 8x - 16\\a=-1,b=-8,c=-16\\D=(-8)^2-4*(-1)*(-16)\\D=64-64\\D=0\\$

Hence we have one real root to this quadratic equation.

7 0

2 years ago