<span>The correct answer is b. Option a is incorrect because these models can demonstrate scientific theories, but they don't prove scientific theories (you would need experiments for that). Option c is incorrect because the models aren't always representing something abstract (i.e. DNA is very real, just very small). Option d is incorrect because they don't precisely mimic something in nature, but instead help us visualize something in nature that is difficult to see or comprehend.</span>
The correct order is:
- Action potential arrives at the axon terminal.
- Calcium ions enter the axon terminal.
- Synaptic vesicles fuse to membrane of axon terminal.
- Acetylcholine is released into the synaptic cleft.
- Acetylcholine binds to its receptors on the junctional folds.
- Junctional folds become depolarized.
- Action potential is initiated on the sarcolemma.
Action potential travels through the membrane of the presynaptic cell causing the channels permeable to calcium ions to open. Ca2+ flow through the presynaptic membrane and increase the Ca concentration in the cell which will activate proteins attached to vesicles that contain a neurotransmitter (e.g. acetylcholine). Vesicles fuse with the membrane of the presynaptic cell, thereby release their contents into the synaptic cleft-space between the membranes of the pre- and postsynaptic cells. Neurotransmitter binds to its receptors on the postsynaptic membrane and its binding causes depolarization of the target cell (muscle cell).
Sexual reproduction occurs through the stages of meiosis. Meiosis itself has two different rounds.
In the first round, the cell grows, copies its chromosomes, and readies itself for division (Interphase). Then, the chromosomes themselves condense and match up perfectly with a partner (specifically called a homologue partner) in Prophase I. These partners trade parts in what is called crossing over. This increases genetic diversity because it creates new combinations of chromosomes with unique alleles. After Prophase I, the chromosomes prepare for splitting (Metaphase I), and the homologues are then separated and moved to different sides of the cell (Anaphase I). Lastly, the chromosomes successfully arrive at the opposite ends, forming two daughter cells (Telophase I and Cytokinesis). This ends the first round of meiosis.
In the second round, the cell skips Interphase, but goes through the rest of the phases, resulting in 4 cells.
Answer:
Ownership Rights
Explanation:
I look back in the tutorial and I found the answer word from word there #platolivesmatter
