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lbvjy [14]
4 years ago
6

A redundant constraint is one that: has a zero coefficient for at least one decision variable.

Mathematics
1 answer:
pishuonlain [190]4 years ago
3 0

Answer:

b. does not form a unique boundary of the feasible solution space.

Step-by-step explanation:

A constraint that does not form a unique boundary of the feasible solution space is called a redundant constraint.

A redundant constraint does not affect the feasible solution region and it commonly occurs in the real world.

By eliminating redundancy, we can simplify the given model.

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There are 8 members on a board of directors. if they must form a subcommittee of 6 members, how many different subcommittees are
Shtirlitz [24]
1. Given a group of n people. There are C(n, r) ways of forming groups of r out of n.

2. Where C(n, r)=\frac{n!}{r!(n-r)!}

3. For example, given {Andy, John, Julia}. We want to pick 2 people to give a gift: we can pick {(Andy, John), (Andy, Julia), (John, Julia)}, so there are 3 ways. So we can list and count.

4. Or we could do this with the formula C(3, 2)=\frac{3!}{2!(1)!}= \frac{3*2*1}{2*1}=3

5. C(8, 6)=\frac{8!}{2!6!}= \frac{8*7*6!}{2*6!}= \frac{8*7}{2}= 4*7=28

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5 0
3 years ago
A parabola can be drawn given a focus of (-11, -2) and a directrix of x= -3
fgiga [73]

Check the picture below, so the parabola looks more or less like that.

now, the vertex is half-way between the focus point and the directrix, so that puts it where you see it in the picture, and the horizontal parabola is opening to the left-hand-side, meaning that the distance "P" is negative.

\textit{horizontal parabola vertex form with focus point distance} \\\\ 4p(x- h)=(y- k)^2 \qquad \begin{cases} \stackrel{vertex}{(h,k)}\qquad \stackrel{focus~point}{(h+p,k)}\qquad \stackrel{directrix}{x=h-p}\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix}\\\\ \stackrel{"p"~is~negative}{op ens~\supset}\qquad \stackrel{"p"~is~positive}{op ens~\subset} \end{cases} \\\\[-0.35em] \rule{34em}{0.25pt}

\begin{cases} h=-7\\ k=-2\\ p=-4 \end{cases}\implies 4(-4)[x-(-7)]~~ = ~~[y-(-2)]^2 \\\\\\ -16(x+7)=(y+2)^2\implies x+7=-\cfrac{(y+2)^2}{16}\implies x=-\cfrac{1}{16}(y+2)^2-7

8 0
2 years ago
HELP!!<br> This is for my geometry exam and i don’t understand <br> please help
rusak2 [61]

Answer:

Step-by-step explanation:

Sin 58° = 0.848 = BC/13

So

BC = 0.848*13 = 11.024

4 0
3 years ago
-4(r+2)=4(2-4r)<br><br>solve for r and show work please
navik [9.2K]
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3 years ago
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professor190 [17]

Answer:

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Multiply 795 by .25

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7 0
3 years ago
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