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pochemuha
3 years ago
10

each pail of plaster covers 90 square feet of ceiling. What is the least number of pails of plaster you would need to buy to cov

er the ceiling of a room with walls 14 feet long?
Mathematics
2 answers:
Dominik [7]3 years ago
7 0
The area of the ceiling:
 A = 14² = 196 ft²
 We need plaster to cover 196 ft².
 196 : 90 = 2.17778
 Answer:  We have to buy 3 pails of plaster.
noname [10]3 years ago
4 0

Answer:

3

Step-by-step explanation:

ik

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Answer: Maria has 10 bills of 5€ and 10 bills of 10€.

She has a total of 150€.

Step-by-step explanation:

Let be "f" the number of 5€ bills that Maria has and "t" the number of 10€ bills that Maria has.

Set up a system of equations:

\left \{ {{f+t=20} \atop {5f+10t=10f+5t}} \right.

Use the Substitution method to solve the system of equations:

1. Solve for "f" from the first equation:

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2. Substitute the equation obtained into the second equation and solve for "t".

Then:

5(20-t)+10t=10(20-t)+5t\\\\100-5t+10t=200-10t+5t\\\\20t-10t=100\\\\t=\frac{100}{10}\\\\t=10

3. Substitute the value of "t" into the equation f=20-t and evaluate:

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Therefore, Maria has 10 bills of 5€ and 10 bills of 10 €.

So the total amount of money she has, is:

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She has a total of 150€.

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