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3 years ago

10

each pail of plaster covers 90 square feet of ceiling. What is the least number of pails of plaster you would need to buy to cov

er the ceiling of a room with walls 14 feet long?

2 answers:

Dominik [7]3 years ago

7 0

The area of the ceiling:
A = 14² = 196 ft²
We need plaster to cover 196 ft².
196 : 90 = 2.17778
Answer: We have to buy 3 pails of plaster.

noname [10]3 years ago

4 0

Answer:

3

Step-by-step explanation:

ik

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Answer:

$Owl= 67.14ft$

Step-by-step explanation:

<em>See comment for complete question.</em>

The given information is represented in the attached figure.

First convert 22°8'6'' and 30° 40’ 30” to degrees

$22^{\circ} 8'6'' = 22 + \frac{8}{60} + \frac{6}{3600}$

$22^{\circ} 8'6'' = 22.135^{\circ}$

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$30^{\circ} 40'30'' = 30.675^{\circ}$

Considering Jason's position:

$tan(22.135^{\circ}) = \frac{H}{x + 48}$

Where x = distance between the tree and Alison

Make H the subject

$H = (x + 48)tan(22.135^{\circ})$

Considering Alison's position

$tan(30.675^{\circ}) = \frac{H}{x}$

Make H the subject

$H = xtan(30.675^{\circ})$

$H = H$

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Open bracket

$x *0.4068 + 48 *0.4068 = 0.5932x$

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Collect Like Terms

$-0.5932x+0.4068x = -19.5264$

$-0.1864x = -19.5264$

$0.1864x = 19.5264$

Make x the subject

$x = \frac{19.5264}{0.1864}$

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$H = 104.76 * tan(30.675^{\circ})$

$H = 104.76 * 0.5932$

$H = 62.14$

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$Owl= H + 5$

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Vcylinder-Vsphere=water

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Answer:

Step-by-step explanation:

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