Answer:
(19/99) = 0.192
Step-by-step explanation:
Numbers 1 to 99, that is 99 numbers (obtained through the equation for the nth term of an AP)
L = a + (n-1) d
L = nth term = 99
a = first term = 1
n = number of terms = ?
d = common difference = 1
99 = 1 + (n-1)1
n = 99
Sample space = 99
The numbers that include at least, a 1 are
1, 10, 11, 12, 13, 14, 15, 16, 17, 18, 19, 21, 31, 41, 51, 61, 71, 81, 91
19 numbers.
Probability of randomly selecting a card where the number contains at least one digit 1 from 1 to 99 = (19/99) = 0.192
Hope this Helps!!!
