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drek231 [11]
3 years ago
8

Harriet earns the same amount of money each day. Her gross pay at the end of 7 work days is 35h + 56 dollars. Which expression r

epresents her gross pay each day?
Mathematics
1 answer:
Aleks [24]3 years ago
8 0

Answer:

<em>The expression that represents her gross pay each day will be:  (5h+8) dollars.</em>

Step-by-step explanation:

Suppose, Harriet's gross pay each day = x

So, her total gross pay for 7 work days =7*x= 7x

Given that, her gross pay at the end of 7 work days is (35h + 56) dollars.

So, the equation will be.......

7x= 35h+56 \\ \\ x=\frac{35h+56}{7}\\ \\ x=\frac{35h}{7}+\frac{56}{7}\\ \\ x=5h+8

Thus, the expression that represents her gross pay each day will be:  (5h+8) dollars.

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Write a quadratic equation with the given roots. Write the equation in the form of ax^2+bx+c=0 where a b and c are integers
Bas_tet [7]

You haven't provided the required roots, but I can tell you how to do this kind of exercises in general.

If the x^2 coefficient is 1, i.e. the equation is written like x^2+bx+c=0, then you can say the following about the coefficients b and c:

  • b is the opposite of the sum of the roots
  • c is the multiplication of the roots.

So, for example, if we want an equation whose roots are 4 and -2, we have:

  • 4+(-2) = 4-2 = 2 \implies b = -2
  • 4 \cdot (-2) = -8 \implies c = -8

So, the equation is x^2-2x-8=0

If your roots are rational, you can work like this: suppose you want an equation with roots 3/4 and 1/2. You have:

  • \dfrac{3}{4}+\dfrac{1}{2} = \dfrac{3}{4}+\dfrac{2}{4} = \dfrac{5}{4} \implies b = -\dfrac{5}{4}
  • \dfrac{3}{4} \cdot \dfrac{1}{2} = \dfrac{3}{8} \implies c = \dfrac{3}{8}

And so the equation is

x^2 - \dfrac{5}{4} + \dfrac{3}{8} = 0

In order to have integer coefficients, you can multiply both sides of the equation by 8:

8x^2 - 10 + 3 = 0

5 0
3 years ago
Please help me w the answer
evablogger [386]

Answer:

\frac{2(x-6)(x-10)}{(x-4)(x-5)}

Step-by-step explanation:

In essence, one needs to work their way backwards to solve this problem. Use the information to construct the function.

The function has verticle asymptotes at (x = 4) and (x = 5). This means that the denominator must have (x - 4) and (x - 5) in it. This is because a verticle asymptote indicates that the function cannot have a value at these points, the function jumps at these points. This is because the denominator of a fraction cannot be (0), the values (x - 4) and (x - 5) ensure this. Since if (x) equals (4) or (5) in this situation, the denominator would be (0) because of the zero product property (this states that any number times zero equals zero). So far we have assembled the function as the following:

\frac{()}{(x-4)(x-5)}

The function has x-intercepts at (6, 0), and (0, 10). This means that the numerator must equal (0) when (x) is (6) or (10). Using similar logic that was applied to find the denominator, one can conclude that the numerator must be ((x - 6)(x-10)). Now one has this much of the function assembled

\frac{(x-6)(x-10)}{(x-4)(x-5)}

Finally one has to include the y-intercept of (0, 120). Currently, the y-intercept is (60). This is found by multiplying the constants together. (6 * 10) equals (60). One has to multiply this by (2) to get (120). Therefore, one must multiply the numerator by (2) in order to make the y-intercept (120). Thus the final function is the following:

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