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8090 [49]
3 years ago
8

Do #1 a-f please 15 points

Mathematics
2 answers:
Luda [366]3 years ago
8 0

Answer:

1a  expression

1b equation

1c equation

1d expression

1e expression

1f equation

Step-by-step explanation:

Equations have an equals sign, expressions do not

1a  expression

1b equation

1c equation

1d expression

1e expression

1f equation

Kitty [74]3 years ago
7 0

Answer:

A Expression B Equation 2 1/4 C Equation 3 2/3 D Expression E Expression F Equation  

Step-by-step explanation:

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Given two trig ratios find the third!
brilliants [131]

Answer:

Step-by-step explanation:

tanA = sinA/cosA = (4/7)/(3/7) = 4/3

7 0
3 years ago
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What are the coordinates of the circumcenter of a triangle with vertices A(4,10), B(10, 10) , and C(10, 2) ?
const2013 [10]

Answer:

(7,6)

Step-by-step explanation:

Triangle ABC with vertices at points A(4,10), B(10, 10) , and C(10, 2) is a right triangle with the hypotenuse AC.

The circumcenter of the right triangle is the midpoint of the hypotenuse.

Find the coordinates of the midpoint O of the hypotenuse AC:

x_O=\dfrac{4+10}{2}=7\\ \\y_O=\dfrac{10+2}{2}=6

So, O(7,6)

4 0
3 years ago
F(x)=-5x. g(x)=8x^2-5x-9. Find: (f*g) (x)
Troyanec [42]
F(x) = -5x
g(x) = 8x² - 5x - 9

(f×g)(x) = ?
= ((-5x)(8x²-5x-9))
= -40x³ + 25x² + 45x → The answer Opsi D
5 0
4 years ago
Rachel ordered early learning software for her daughter from an online retailer. Each item costs
andre [41]

Answer:

60$

Step-by-step explanation:

Shipping is 7.50 and the 7 items are 52.5 total

4 0
3 years ago
Write an equation of the line containing the point (3,5) and perpendicular to the line 4x-3y=5
ICE Princess25 [194]

Answer:

Step-by-step explanation:

In order to write the equation of the line perpendicular to the given line, we first have to know what the slope of the given line is, and there's no way to tell by looking at it in its current form, which is standard. We need to solve that equation for y to determine the slope of that line. Solving for y:

-3y=-4x+5 and

3y = 4x - 5 (just change all the signs so our y term isn't negative anymore...yes, you're "allowed" to do that!) and

y=\frac{4}{3}x-\frac{5}{3} So we can see now that the slope of this line is 4/3. That means that the perpendicular slope is -3/4. Passing through the given point (3, 5):

y-5=-\frac{3}{4}(x-3)* and

y-5=-\frac{3}{4}x+\frac{9}{4} and

y=-\frac{3}{4}x+\frac{9}{4}+\frac{20}{4} so

y=-\frac{3}{4}x+\frac{29}{4}** and, in standard form:

4y = -3x + 29 and

3x + 4y = 29***

* : point-slope form

** : slope-intercept form

*** : standard form

3 0
3 years ago
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