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tiny-mole [99]
3 years ago
5

The radius of a circle is 6 kilometers. What is the area of a sector bounded by a 45° arc?

Mathematics
1 answer:
Drupady [299]3 years ago
3 0

here's the solution,

Area of sector =

\frac{ 45}{360}  \times \pi \times 6 \times 6

=》

\frac{36\pi}{8}

=》

\frac{9 \times 3.14}{2}

=》

9 \times 1.57

=》14.13 km²

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Ede4ka [16]

We will see that the solution in the given interval is: x = 0.349 radians.

<h3>How to solve equations with the variable in the argument of a cosine?</h3>

We want to solve:

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Here we must use the inverse cosine function, Acos(x). Remember that:

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If we apply that in both sides, we get:

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7 0
2 years ago
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SSSSS [86.1K]

Answer:

For 2017 Season:

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For 2018 Season:

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Step-by-step explanation:

The following formulas will be used in these calculations:

Mean = (sum of the values) / n

Variance = ((Σ(x - mean)^2) / (n - 1)

Standard deviation = Variance^0.5

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Mean = (73 + 77 + 78 + 76 + 74 + 72 + 74 + 76) / 8 = 600 / 8 = 75

Variance = ((73-75)^2 + (77-75)^2 + (78-75)^2 + (76-75)^2 + (74-75)^2 + (72-75)^2 + (74-75)^2 + (76-75)^2) / (8-1) = 30 / 7 = 4.29

Standard deviation = Variance^0.50 = 4.29^0.5 = 2.07

For 2018 Season

Mean = (70 + 69 + 74 + 76 + 84 + 79 + 70 + 78) / 8 = 75

Variance = ((70-75)^2 + (69-75)^2 + (74-75)^2 + (76-75)^2 + (84-75)^2 + (79-75)^2 + (70-75)^2 + (78-75)^2) / (8-1) = 194 / 7 = 27.71

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3 years ago
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Answer:

52

Step-by-step explanation:

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