The surface area of the pyramid is 576.
<em>The square base is 144. It's just a square, so you multiply 12 (length) and 12 ( width) , which equals 144. </em>
<em>Then you find the area of one of the triangles. The equation to find triangles goes like this: 0.5 x B (base: 12) x H (height: 18). That would be 6 x 18 which is 108.</em>
<em>Since you got the area of 1 triangle and there are 4 triangles you have to multiply 108 by 4. That'll give you 432.</em>
<em>SO since you have the area of all the triangles and the square base the last thing you have to do is just add it all up. </em>
<em>The area of the triangles plus the area of the square base = the surface area.</em>
<u>432 cm + 144 cm =576 cm.</u>
Regular hexagon consists of six equilateral triangles. The angle of a hexagon is equal to the sum of two angles in an equilateral triangle.
PN = PM
6x + 1 = 10x - 17
Add both sides 17
6x + 1 + 17 = 10x - 17 + 17
6x + 18 = 10x
Subtract both sides 6x
6x - 6x + 18 = 10x - 6x
18 = 4x
Divide both sides by 4
18 ÷ 4 = 4x ÷ 4
9/2 = x
x = 9/2
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QN = 2x + 5
QN = 2 × ( 9/2 ) + 5
QN = 9 + 5
QN = 14
C = 5/9(F - 32)....when F = 32...so sub in 32 for F
C = 5/9(32 - 32)
C = 5/9(0)
C = 0
so at 32 F, it is 0 C
Step-by-step explanation:
1) 15 % games lost
2) 3/20
3) 271/500
4) 12/25