By definition, rational numbers are numbers that ca be expressed as a fraction that either terminates when divided or repeats when divided. Integers, on the other hand CANNOT be fractions, so integers are more specific than rational numbers. So the first statement above is not true. I just stated that repeating decimals are rational, so the second statement is not true either. When you divide 715 by -14 you get a number that appears to not terminate or repeat, so the third statement down is true. Terminating decimals are rational, so the fourth statement down is true. As for the last one, I am assuming that the ..... you have after that number means it goes on and on and since it doesn't repeat within those numbers you've listed there I'm assuming that it doesn't repeat or terminate so it is not a rational number. The only 2 statements that are true (or "apply", according to your instructions) are the third and the fourth statements down.
Answer:
D
x is less than or equal to -3
Step-by-step explanation:
I hope I was fast enough ^^
5 rational numbers between 0.5 and 0.6 can be any 5 numbers up to any number of decimal places that lies between 0.5 and 0.6. Or, it can also be 0.5124, 0.5676, 0.588, 0.59, 0.5789.S
Answer:
The leading coefficient is 1 and the linear term coefficient is an even number
Step-by-step explanation:
Leading coefficient must be one for the application of completing square method. If the completing square is not one than we must apply other methods like Ac method, quadratic formula to solve the equation. To solve the equation with completing square the numerical value must be on other side of the equation. In this method we multiply linear term’s coefficient with one-half and square it therefore, completing square is suitable method for the equation having leading coefficient is 1 and linear coefficient is even.
Answer:
(1, 5)
Step-by-step explanation:
The solution to the system of equations is the point of intersection of the two lines. From inspection of the graph, the point of intersection is at (1, 5).
<u>Proof</u>
The solution to a system of equations is the point at which the two lines meet.
⇒ g(x) = f(x)
⇒ 3x + 2 = |x - 4| + 2
⇒ 3x = |x - 4|
⇒ 3x = x - 4 and 3x = -(x - 4)
⇒ 3x = x - 4
⇒ 2x = -4
⇒ x = -2
Inputting x = -2 into the 2 equations:
⇒ g(-2) = 3 · -2 + 2 = -4
⇒ f(-2) = |-2 - 4| + 2 = 8
Therefore, as the y-values are different, x = -2 is NOT a solution
⇒ 3x = -(x - 4)
⇒ 3x = 4 - x
⇒ 4x = 4
⇒ x = 1
Inputting x = 1 into the 2 equations:
⇒ g(1) = 3 · 1 + 2 = 5
⇒ f(1) = |1 - 4| + 2 = 5
Therefore, as the y-values are the same, x = 1 IS a solution
and the solution is (1, 5)
