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Zigmanuir [339]
3 years ago
5

Find the y intercept (-3,19) and (6,13)

Mathematics
1 answer:
leva [86]3 years ago
3 0

Answer:

Step-by-step explanation:

We will first find the slope of the line from those 2 points, then write the equation of the line in slope-intercept form, solving for b, the y-intercept.

m=\frac{13-19}{6-(-3)}=-\frac{6}{9}=-\frac{2}{3}

So the slope is -2/3.  We will choose a point now to use in the slope-intercept equation.  I'm picking the one with no negatives (cuz who likes negatives!?).

13=-\frac{2}{3}(6)+b which simplifies down to

13 = -4 + b so

b = 17

The y-intercept of the line that goes through those 2 points is (0, 17)

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Answer:

m = 9

Step-by-step explanation:

-2m + 8 + m + 1 = 0

-m + 9 = 0

9 = m

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Suppose 5 men and 7 women are on a crowded elevator. At the next floor, four people get off the elevator. Find the probability t
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Answer:

0.141

Step-by-step explanation:

There are ₇C₁ ways to choose 1 woman from 7.

There are ₅C₃ ways to choose 3 men from 5.

There are ₁₂C₄ ways to choose 4 people from 12.

So the probability is:

₇C₁ ₅C₃ / ₁₂C₄

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Ms. Lady works-out with Ms. Beetle; her average crawling time has increased to 4 feet per minute, while Ms. Beetle, who is used
ira [324]

Answer:

Senn needs to give Ms. Lady 4.6 minutes  head start

Senn needs to give Ms. Beetle 18.4 minutes  head start

The equation for each bug are;

For Senn, the equation for the experiment is 5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is 4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is 4 × (t₁ + 18.4) = 92 feet

Please find attached the required graph and table of values

Step-by-step explanation:

The given parameters are;

The average crawling time of Ms. Lady = 4 feet per minute

The average crawling time of Ms. Beetle = 2.5 feet per minute

The average crawling time of Senn = 5 feet per minute

The distance to the rose bush = 92 feet

Therefore, we have;

The time, t, duration for Senn to arrive at the Rose bush is given by the following relation,

Time, t = Distance, d/(Speed, s)

Given that the speed of the bugs is equal to their average crawling time, we have

For Senn

Time, t = 92/(5 ft/Min) = 18.4 minutes

For, Ms. Lady

Time, t = 92/(4 ft/Min) = 23 minutes

For, Ms. Beetle

t = 92/(2.5 ft/Min) = 36.8 minutes

Therefore;

Senn needs to give Ms. Lady 23 - 18.4 = 4.6 minutes head start

Similarly, Senn needs to give Ms. Beetle 36.8 - 18.4 = 18.4 minutes  head start

The equation for each bug are therefore;

For Senn, the equation for the experiment is given as follows ;

5 × t₁ = 92 feet

For Ms. Lady, the equation for the experiment is given as follows;

4 × (t₁ + 4.6) = 92 feet

For Ms. Beetle , the equation for the experiment is given as follows;

4 × (t₁ + 18.4) = 92 feet.

7 0
3 years ago
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