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LenKa [72]
3 years ago
8

Write a program that asks the user to guess the next roll of a six-sided die. Each guess costs $ 1. If they guess correctly, the

y get $ 100.00. The player will start out with a $10.00 bank. Each time he (or she) guesses incorrectly you will subtract $1.00 from their bank. Each time they guess correctly, you add $10.00 to their bank. Print the total winnings or losses at the end of the game. You can simulate the toss of the dice using the RandomRange function (Don't forget to Randomize).
Computers and Technology
1 answer:
jasenka [17]3 years ago
3 0

Answer in python:

import random

money = 10

winnings = 0

def main():

global winnings

global money

dice_num = random.randrange(1,6)

input_str = "Guess the dice number. You have $"+str(money)+" > "

input_num = input(input_str)

if int(input_num) == dice_num:

 money = money + 10

 winnings = winnings + 10

else:

 money = money - 1

if money < 0:

 print("You lose. You won "+str(winnings)+" times. Press enter to try again")

 useless_variable = input()

 main()

else:

 main()  

main()

Explanation:

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Which of the following are true if you pay only the minimun amount each month towards your credit card bill? You will be charged
torisob [31]

Both A and B are true. Check out this link: https://www.nerdwallet.com/blog/credit-cards/minimum-payment-credit-card/

I hope this helps!

6 0
3 years ago
A compression scheme for long strings of bits called run-length encoding is described as follows: Rather than record each 0 and
Musya8 [376]

Answer: (B) Lossless compression

Explanation:

 According to the question, the given technique is the example of the lossless compression. The lossless compression is one of the technique that decompress the data into the original data form without any type of losses.

The lossless compression is the technique that usually compress the data, text and the databases. This technique also improve the compression rate helps in reconstruct the original data. It is used in various types of encoding methods, GNU tool and zip file.

3 0
3 years ago
The intention of this problem is to analyze a user input word, and display the letter that it starts with (book → B).
yulyashka [42]

Answer:

Here is the C++ program:

#include<iostream>  // to use input output functions

using namespace std;     //to identify objects like cin cout

void StartChar(string str)  {  // function that takes a word string as parameter and returns the first letter of that word in capital

   int i;  

   char c;

   do  //start of do while loop

   {

   for (int i = 0; i < str.length(); i++) {  //iterates through each character of the word str

       if(str.length()>25){  //checks if the length of input word is greater than 25

           cout<<"limit exceeded"; }  //displays this message if a word is more than 25 characters long

      c = str.at(i);   // returns the character at position i

       if (! ( ( c >= 'a' && c <= 'z' ) || ( c >= 'A' && c <= 'Z' ) ) ) {  //checks if the input word is contains characters other than the alphabet

            cout<<str<<" is not a word!"<<endl; break;}  //displays this message if user enters characters other than the alphabet

        if (i == 0) {  //check the first character of the input word

           str[i]=toupper(str[i]);  //converts the first character of the input word to uppercase

           cout<<str<<" starts with letter "<<str[i]<<endl;  }  // prints the letter that the word starts with in capital letter

   }   cout<<"Enter a word: ";  //prompts user to enter a word

      cin>>str;   //reads input word from user

}while(str!="#");   }    //keeps prompting user to enter a word until the user enters #

int main()   //start of the main() function body

{ string str;  //declares a variable to hold a word

cout<<"Enter a word: "; //prompts user to enter a word

cin>>str; //reads input word from user

   StartChar(str); }  //calls function passing the word to it

     

Explanation:

The program prompts the user to enter a word and then calls StartChar(str) method by passing the word to the function.

The function StartChar() takes that word string as argument.

do while loop starts. The for loop inside do while loop iterates through each character of the word string.

First if condition checks if the length of the input word is greater than 25 using length() method which returns the length of the str. For example user inputs "aaaaaaaaaaaaaaaaaaaaaaaaaaa". Then the message limit exceeded is printed on the screen if this if condition evaluates to true.

second if condition checks if the user enters anything except the alphabet character to form a  word. For example user $500. If this condition evaluates to true then the message $500 is not a word! is printed on the screen.

Third if condition checks if the first character of input word, convert that character to capital using toupper() method and prints the first letter of the str word in capital. For example if input word is "Computer" then this prints the message: Computer starts with the letter C in the output screen.

The program keeps prompting the user to enter the word until the user enters a hash # to end the program.

The output of the program is attached.

3 0
3 years ago
3.26 LAB: Leap Year A year in the modern Gregorian Calendar consists of 365 days. In reality, the earth takes longer to rotate a
Tju [1.3M]

Answer:

year = int(input("Enter a year: "))

if (year % 4) == 0:

  if (year % 100) == 0:

      if (year % 400) == 0:

          print(str(year) + " - leap year")

      else:

          print(str(year) +" - not a leap year")

  else:

      print(str(year) + " - leap year")

else:

  print(str(year) + "- not a leap year")

Explanation:

*The code is in Python.

Ask the user to enter a year

Check if the <u>year mod 4</u> is 0 or not. If it is not 0, then the year is not a leap year. If it is 0 and if the <u>year mod 100</u> is not 0, then the year is a leap year. If the <u>year mod 100</u> is 0, also check if the <u>year mod 400</u> is 0 or not. If it is 0, then the year is a leap year. Otherwise, the year is not a leap year.

8 0
3 years ago
Read 2 more answers
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