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3 years ago

En un paralelogramo de tiene ?

Mathematics

1 answer:

soldi70 [24.7K]3 years ago

6 0

Answer:

Elementos y propiedades del paralelogramo

Lados: el paralelogramo tiene cuatro lados, siendo iguales y paralelos dos a dos (a y b). Ángulos: los ángulos interiores son iguales dos a dos, siendo iguales los ángulos no consecutivos (α y β). Como en todo cuadrilátero, sus ángulos interiores suman 360° (2α + 2β = 360°)

Step-by-step explanation:

Elements and properties of the parallelogram

Sides: the parallelogram has four sides, two by two (a and b) being equal and parallel. Angles: the interior angles are equal two by two, the non-consecutive angles (α and β) being equal. As in any quadrilateral, its interior angles add up to 360 ° (2α + 2β = 360 °) (English version lol)

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Help pleasseee what’s the area

True [87]

First, we need to find the missing leg of triangle ACD. We have to use pythagorean theorem to find the missing leg.

a^2 + b^2 = c^2

In this problem,

a = 2

b = ?

c = 5

Plug our numbers into the formula above.

2^2 + b^2 = 5^2

Simplify our terms

4 + b^2 = 25

Subtract 4 from both sides

b^2 = 21

Take the square root of each side

b = √(21)

Now, we can solve for the area of triangle ABC

Area of a triangle = (h * b) / 2

h = height

b = base

In this problem,

h = √(21)

b = 5.0

Plug our numbers into the area formula of a triangle

Area = (√(21) * 5) / 2 = 11.46 square units

8 0

3 years ago

Please please please need help on 3 and 4 I’m really lost on them

Alex73 [517]

Answer:

1) Option c) is correct ie., 5 real and o non-real

2) Option b) is correct ie., (4, $\frac{1}{2}$ , $\frac{1}{2}$ , 2,2)

Step-by-step explanation:

Given polynomial function is $f(x)=x^5-3x^3-2$

To find zeros equate f(x) to zero ie., $f(x)=0$

$x^5-3x^3-2=0$

By synthetic division

| 1 0 -3 0 -2

-1 | 0 -1 1 2 2

|_________________

1 -1 -2 2 0

Therefore x=-1 is a zero

$x^3-x^2-2x+2=0$

| 1 -1 -2 2

1 | 0 1 0 2

|___________________

1 0 -2 0

x=1 is the zero

$x^2 -2 =0$

$x=\pm\sqrt{2}$

$x=\sqrt{2}$ and

$x=\sqrt{-2}$

Option c) is correct ie., 5 real and o non-real

2) Given polynomial function is $f(x)=(x-4)(2x-1)^2(x-2)^2$

To find zeros equate f(x) to zero ie., $f(x)=0$

$(x-4)(2x-1)^2(x-2)^2=0$

$(x-4)=0$ (or) $(2x-1)^2=0$ or $(x-2)^2=0$

Therefore x=4, $x=\frac{1}{2}$ of multiplicity of 2 and x=2 multiplicity of 2

Option b) is correct ie., (4, $\frac{1}{2}$ , $\frac{1}{2}$ , 2,2)

5 0

4 years ago

6(x + 2) = 2(x + 10)

sineoko [7]

6(x + 2) = 2(x + 10)
6x + 12 = 2x + 20
6x - 2x = -12 + 20
4x = 8
x = 8/4
x = 2

3(y - 4) + 2 = 5y - 28
3y - 12 + 2 = 5y - 28
3y -10 = 5y - 28
3y - 5y = 10 - 28
-2y = -18
y = -18/-2
y = 9

5(2z - 3) - 3z = 3(z + 3)
10z - 15 - 3z = 3z + 9
7z - 15 = 3z + 9
7z - 3z = 15 + 9
4z = 24
z = 24/4
z = 6

4 0

3 years ago

Read 2 more answers

What is the reciprocal of 7 1/3

Akimi4 [234]

First, you have to change 7 1/3 to an improper fraction which is 22/3.
Then you have to flip the fraction upside down to get the reciprocal.

So the answer is 3/22

6 0

4 years ago

A bag contains 4 blue and 6 green marbles. Two marbles are selected at random from the bag. If the first marble is not replaced

Tpy6a [65]

It would be a 3:2 chance the first one picked was green and 5:4 chance the second is also green. Hope this helps.

3 0

3 years ago