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2 years ago

1/3 (5)= 1/3 will be the fraction 1 over 3

Mathematics

2 answers:

Mars2501 [29]2 years ago

8 0

Answer: 5/3
(1/3)(5/1)=5/3

lara [203]2 years ago

4 0

Answer:

5/3 or 1.6

Step-by-step explanation:

To solve this, multiply the numerator by 5.

1/3 * 5 = 5/3. We can simplify that into decimal form which is 1.6.

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Write the next three multiples of 9 <br> 36,

GrogVix [38]

Answer:

45,54,63

Step-by-step explanation:

The multiples of 9 are

9,19,27,36,45,54,63,72,81

The three multiples are 36 are

45,54,63

3 0

3 years ago

Read 2 more answers

Mr. Kovich is preparing materials for a craft project. He needs to cut 2 meters of string into pieces that are 0.2 meters long.

kondor19780726 [428]

Answer:

10 pieces

Step-by-step explanation:

2 divided by 0.2

20 divided by 2

10 pieces

8 0

3 years ago

(2)+(-13)=<br>whats the answer?

ziro4ka [17]

Answer:

$- 11$

Step-by-step explanation:

$2 + ( - 13) \\ 2 - 13 = - 11$

5 0

3 years ago

Help me please explain

Vera_Pavlovna [14]

Answer:

x=6,-4

Step-by-step explanation:

Ok so we know the 2 angles are congruent so you need to set them equal to each other. x^2+5x=7x+24. Then get the x's together so you subtract by 7x to get x^2-2x=24. You would then get 24 on the other side so subtract by 24 to get x^2-2x-24. You then would need to factor the equation out. The factored form would be (x-6)(x+4). Then set it equal to 0 to get 6 and -4.

7 0

2 years ago

An automobile manufacturer would like to know what proportion of its customers are not satisfied with the service provided by th

butalik [34]

Answer:

a) A sample size of 5615 is needed.

b) 0.012

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

The margin of error is:

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

99.5% confidence level

So $\alpha = 0.005$ , z is the value of Z that has a pvalue of $1 - \frac{0.005}{2} = 0.9975$ , so $Z = 2.81$ .

(a) Past studies suggest that this proportion will be about 0.2. Find the sample size needed if the margin of the error of the confidence interval is to be about 0.015.

This is n for which M = 0.015.

We have that $\pi = 0.2$

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$0.015 = 2.81\sqrt{\frac{0.2*0.8}{n}}$

$0.015\sqrt{n} = 2.81\sqrt{0.2*0.8}$

$\sqrt{n} = \frac{2.81\sqrt{0.2*0.8}}{0.015}$

$(\sqrt{n})^{2} = (\frac{2.81\sqrt{0.2*0.8}}{0.015})^{2}$

$n = 5615$

A sample size of 5615 is needed.

(b) Using the sample size above, when the sample is actually contacted, 12% of the sample say they are not satisfied. What is the margin of the error of the confidence interval?

Now $\pi = 0.12, n = 5615$ .

We have to find M.

$M = z\sqrt{\frac{\pi(1-\pi)}{n}}$

$M = 2.81\sqrt{\frac{0.12*0.88}{5615}}$

$M = 0.012$

7 0

3 years ago