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olya-2409 [2.1K]
3 years ago
6

I will gib brainliest if u help me >:C

Mathematics
1 answer:
zzz [600]3 years ago
6 0

Answer:

1,800

Step-by-step explanation:

Why is because 6 is over for and u estimate to the nearest hundredth and then again the six is still there so u estimate the with the 100 place with give u a 800 so its 1,800

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Read 2 more answers
the polynomial ky^3+3y^2-3 and 2y^3-5y+k when divided by (y-5) leave the same remainder in each case. Find the value of k.
marshall27 [118]

Answer:

k=\frac{153}{124}

Step-by-step explanation:

According to the Remainder Theorem; when P(y) is divided by y-a, the remainder is p(a).

The first polynomial is :

p(y)=ky^3+3y^2-3

When p(y) is divided by y-5, the remainder is

p(5)=k(5)^3+3(5)^2-3

p(5)=125k+75-3

p(5)=125k+72

When the second polynomial:

m(y)= 2y^3-5y+k is divided by y-5.

The remainder is;

m(5)= 2(5)^3-5(5)+k

m(5)= 225+k

The two remainders are equal;

\implies 125k+72=225+k

\implies 125k-k=225-72

\implies 124k=153

k=\frac{153}{124}

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