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rusak2 [61]
3 years ago
9

1?

Mathematics
1 answer:
hichkok12 [17]3 years ago
6 0

answer:

1.57 cm

Step-by-step explanation:

pi = 3.14

circumference of circle = pi x diameter

3.14 x 2 = 6.28

90/360 x 6.28 = 1.57

the arc length = 1.57 provided that 3.14 is used as pi.

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Tell whether the table of values represents a linear function, an exponential function, or a quadratic funtion
gizmo_the_mogwai [7]

Answer:

Step-by-step explanation:

if it is linear then it will be a straight line(gradient is the same)

if quadratic then curve(gradeint isnt the same)

y=mx+c

m=[y(2)-y(1)]/[x(2)-x(1)]

you can choose any 2 points from the table

m=2-0.4/0-1

m=-1.6

repeat but 2 different coordinates

m=0.4-0.08/-1--2==>-2.24

m=-2.24

different coordinate therefore quadratic

cant be exponential, because nothing is being raised to some power

5 0
2 years ago
Simplify (x2y)3. need this asap
bogdanovich [222]

Answer:

3x^2y

Step-by-step explanation:

hope this helps : )

4 0
3 years ago
Triangles 3 and 4 are identical. They are joined in the poster to form a square. Construct a math argument to show why triangles
Bond [772]

Triangles 3 and 4 are isosceles right angles because they have same length.

<h3>How to explain the triangle?</h3>

It should be noted be noted that the square has all right angles equal. The largest angle of the triangle is the right angle m.

Here, the triangles are isosceles right angles as both the legs and the acute angles are congruent.

Learn more about triangles on:

brainly.com/question/17335144

#SPJ1

7 0
2 years ago
If 1st and 4tg terms of G.p are 500 and 32 respectively it's second term is ?
bixtya [17]

Answer:

T_{2} = 200

Step-by-step explanation:

Given

Geometry Progression

T_1 = 500

T_4 = 32

Required

Calculate the second term

First, we need to write out the formula to calculate the nth term of a GP

T_n = ar^{n-1}

For first term: Tn = 500 and n = 1

500 = ar^{1-1}

500 = ar^{0}

500 = a

a = 500

For fought term: Tn = 32 and n = 4

32 = ar^{4-1}

32 = ar^3

Substitute 500 for a

32 = 500 * r^3

Make r^3 the subject

r^3 = \frac{32}{500}

r^3 = 0.064

Take cube roots

\sqrt[3]{r^3} = \sqrt[3]{0.064}

r  = \sqrt[3]{0.064}

r = 0.4

Using:  T_n = ar^{n-1}

n = 2     r = 0.4     and a = 500

T_{2} = 500 * 0.4^{2-1}

T_{2} = 500 * 0.4^1

T_{2} = 500 * 0.4

T_{2} = 200

<em>Hence, the second term is 200</em>

5 0
3 years ago
Is x=3 a solution for the equation: 3x + 7 = 13<br> Why or why not ?
expeople1 [14]

Answer:

No.

Step-by-step explanation:

There are two different ways to do this - solve for x in the given equation or substitute the value for x and see if you get a true statement.

3x + 7 = 13 subtract 7 from both sides

3x = 6 divide by 3 on both sides

x = 2

3(3) + 7 = 13

9 + 7 = 13

16 ≠ 13

Therefore, x = 3 is not a solution for 3x + 7 = 13.

5 0
3 years ago
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