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3 years ago

1?

Mathematics

1 answer:

hichkok12 [17]3 years ago

6 0

answer:

1.57 cm

Step-by-step explanation:

pi = 3.14

circumference of circle = pi x diameter

3.14 x 2 = 6.28

90/360 x 6.28 = 1.57

the arc length = 1.57 provided that 3.14 is used as pi.

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A line has an c intercept of 3 and a y intercept of negative 6. What is the slope intercept form of it’s equation

Schach [20]

Answer:

y = 2x - 6

Step-by-step explanation:

Slope-intercept form is y = mx + b, where m is the slope and b is the y-intercept.

The y-intercept is already given and is -6.

By c intercept, I am assuming you meant x-intercept. With an x-intercept of 3, the point is (3,0). With a y-intercept of -6, the point is (0,-6).

Use the two points to find the slope using the following equation.

$m=\frac{y_{2}-y_{1} }{x_{2}- x_{1} }$

Plug the points into their respective positions and solve.

$m=\frac{-6-0}{0-3}\\ m=\frac{-6}{-3} \\m=2$

The slope is 2.

Your equation is y = 2x - 6.

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3 years ago

Which statements are true? and whos down to talk?

Vladimir [108]

Can’t see the statements

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3 years ago

which of the functions have a range of real numbers greater than or equal to 1 or less than or equal to-1

lilavasa [31]

The question is incomplete. Here is the complete question:

Which of the functions have a range of all real numbers greater than or equal to 1 or less than or equal to -1? check all that apply.

A. $y=\sec x$

B. $y= \tan x$

C. $y= \cot x$

D. $y= \csc x$

Answer:

A. $y=\sec x$

D. $y=\csc x$

Step-by-step explanation:

Given:

The range is greater than or equal to 1 or less than or equal to -1.

The given choices are:

Choice A: $y=\sec x$

We know that, the $\sec x=\frac{1}{\cos x}$

The range of $\cos x$ is from -1 to 1 given as [-1, 1]. So,

$|\cos x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\cos x|}\geq 1\\|\sec x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the secant function as:

$\sec x\leq -1\ or\ \sec x\geq 1\\$

Therefore, the range of $y=\sec x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

Choice B: $y= \tan x$

We know that, the range of tangent function is all real numbers. So, choice B is incorrect.

Choice C: $y= \cot x$

We know that, the range of cotangent function is all real numbers. So, choice C is incorrect.

Choice D: $y=\csc x$

We know that, the $\csc x=\frac{1}{\sin x}$

The range of $\sin x$ is from -1 to 1 given as [-1, 1]. So,

$|\sin x|\leq 1\\\textrm{Taking reciprocal, the inequality sign changes}\\\frac{1}{|\sin x|}\geq 1\\|\csc x|\geq 1$

Therefore, on removing the absolute sign, we rewrite the cosecant function as:

$\csc x\leq -1\ or\ \csc x\geq 1\\$

Therefore, the range of $y=\csc x$ is all real numbers greater than or equal to 1 or less than or equal to-1.

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3 years ago

Find the product or quotient. Express using positive exponents

Alex73 [517]

Answer:

Step-by-step explanation:

$x^{-6}*x^{-5}=x^{(-6)+(-5)}=x^{-11}=\frac{1}{x^{11}}$

$x^{a}*x^{b}=x^{a+b}\\\\x^{-a}=\frac{1}{x^{a}}$

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3 years ago

What is the domain of the function represented by this graph?

Fantom [35]

Domain is all the x values represented
domain here is infinitely because it can go on forever to the left and to the right

8 0

2 years ago