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faust18 [17]
3 years ago
10

A running coach wants to know if participating in weekly running clubs significantly improves the time to run a mile. The runnin

g coach collects mean mile times for 42 runners who participate in weekly running clubs with 54 runners who do not run in clubs. The running coach measures times in January and June of the same year. All times are in seconds, and the runners all started with mile times between 8 minutes (480 seconds) and 9 minutes (540 seconds). Here are the results:
January June Change
Mean (seconds) StDev (seconds) Mean (seconds) StDev (seconds) Mean (seconds) StDev (seconds)
Running Club N = 42 530 28 520 23 10 4
Not in a Club N = 54 527 25 519 22 8 3
What is the best method for the running coach to use to determine if participating in weekly running clubs significantly improves the time to run a mile?
A) Use the difference in sample means (530 – 520) in a hypothesis test for a difference in two population means.
B) Use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.
C) Use the sample mean 10 in a hypothesis test for a population mean.

Mathematics
1 answer:
patriot [66]3 years ago
7 0

Answer:

Option B is correct.

Use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.

Step-by-step Explanation:

The clear, complete table For this question is presented in the attached image to this solution.

It should be noted that For this question, the running coach wants to test if participating in weekly running clubs significantly improves the time to run a mile.

In the data setup, the mean time to run a mile in January for those that participate in weekly running clubs and those that do not was provided.

The mean time to run a mile in June too is provided for those that participate in weekly running clubs and those that do not.

Then the difference in the mean time to run a mile in January and June for the two classes (those that participate in weekly running clubs and those that do not) is also provided.

Since, the aim of the running coach is to test if participating in weekly running clubs significantly improves the time to run a mile, so, it is logical that it is the improvements in running times for the two groups that should be compared.

Hence, we should use the difference in sample means (10 and 8) in a hypothesis test for a difference in two population means.

Hope this Helps!!!

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Answer:

There is no minimum cost for the fencing that can satisfy these conditions.

as the equation obtained for this problem is y = \frac{7x}{x-6}.

Step-by-step explanation:

let length of the rectangular rose garden be x

and breath of the rectangular rose garden be y

then the area of the garden = xy

cost of fencing a foot for the 3 non road sides = $6

and cost of fencing a foot for a road side = $8

total cost of fencing = 6x + 8x + 6y + 6y

so, total cost = 14x + 12y

cost of fencing for every square foot of the area =$2

So, 2xy = 14x + 12y

=> 2xy = 14x + 12y

Also, x and y has to satisfy x>0 and y>0

You can solve for y (or x if you prefer)

2xy-12y=14x

xy - 6y = 7x

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we can check that this function has no minimum value.

as we increase x (starting any x > 6 to make y positive) to make y minimal, y will decrease but the product xy will increase.

So, there is not a minimum cost for fencing that can satisfy these conditions.

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Step-by-step explanation:  

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melamori03 [73]

Answer:

b = 90

Step-by-step explanation:

Sum the interior angles of the pentagon and equate to 540

Starting from the top and going clockwise

b + b + 45 + 90 + 2b - 90 + \frac{3}{2} b = 540 ← simplify left side

\frac{11}{2} b + 45 = 540 ( multiply through by 2 to clear the fraction )

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11b = 990 ( divide both sides by 11 )

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\frac{3}{2} b = \frac{3}{2} × 90 = 135

The angle measure from the top clockwise are

90°, 135°, 90°, 90°, 135°

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Step-by-step explanation:

\left(\frac{-4+10}{2}, \frac{-5-9}{2} \right)=(3, -7)

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