<span>"Stuck-at-0 fault" is a term used to describe what fault simulators use as a fault model to simulate a manufacturing defect. When "stuck-at-fault-0" occurs, one of the wires is broken, and will always register at logical 0</span>
The question is incomplete. Here is the complete question
Suppose the demand for Digital Video Recorders (DVRs) is given by Q = 250 - .25p + 4pc, where Q is the quantity of DVRs demanded (in 1000s), p is the price of a DVR, and pc is the price of cable television. How much does the quantity demanded for DVRs change if the p rises by $40? A) drops by 10,000 DVRs B) increases by 16,000 DVRs C) drops by 2,500 DVRs D) increases by 4,000
Answer:
Drops by 10,000 DVRs
Explanation:
The demand for digital video recorders is expressed by
Q= 250- .25p+4pc
Where
Q represents the quantity demanded by the customers
P represents the price of DVR
pc represents the price of cable television
Since the factor of p in the expression above is negative, this implies that the quantity of DVR demanded in the market will reduce
If the price of DVR increase by $40, then the quantity demanded will reduce by
= 0.25×40×1000
= 10×1000
= 10,000 units
Hence the quantity of DVRs drops by 10,000 DVRs if the price is increased to $40
Answer:
FV= $46,031.45
Explanation:
Giving the following information:
Monthly deposit= $450
Number of months= 59
Interest rate= 0.21/12= 0.0175
To calculate the final value, we need to use the following formula:
FV= {A*[(1+i)^n-1]}/i
A= monthly deposit
FV= {450*[(1.0175^59) - 1]} / 0.0175 + 450
FV= $46,031.45
Answer:
$1615
Explanation:
($575 + 650) 0.10 = $122.50
Find the future value of $122.50
Future value can be calculated using a financial calculator:
$122.50 = PMT
10 = N
6% = I/Y
Press compute then FV
Fv = $1615
I hope my answer helps you
