You can plug -x - 1 for y in the first equation
2x - (-x - 1) = 10
2x + x + 1 = 10
Combine
3x = 9
Divide
x = 3
Plug 3 for x in any equation ( I'll use th second equation )
y = - (3) - 1
y = - 3 - 1 = -4
x = 3 ; y = -4
(3, -4)
The area of the rectangle:
A = Length x Width = JK x KL = 36 cm²
If JK ≥ 4 cm, we have to prove that KL ≤ 9 cm.
Answer:
Assume that a. KL > 9 cm.
Then the area of rectangle JKLM is greater than b. 36 cm²,
which contradicts the given information that c. side is at least 4 cm long.
So the assumption must be false. Therefore, d. KL ≤ 9 cm.
I’m struggling too I’m sorry
Answer:
nine over eleven because its ez
Step-by-step explanation:
Answer: x = 4,11
Step-by-step explanation:
x^2 - 7x - 34 - 10 = 0
x^2 - 7x - 44 = 0
Factorise it
x^2 - 11x - 4x - 44 = 0
x ( x - 11 ) - 4 ( x - 11 ) = 0
(x-4)(x-11) = 0
x = 4,11
