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Norma-Jean [14]
2 years ago
15

Harold purchased a new snowmobile. The dealer gave him an option to pay the purchase price of x dollars at 100 dollars per month

for y months. He would pay the remaining balance amount the following month. Which type of payment plan did the dealer offer Harold?
The dealer gave Harold
The dealer gave Harold (a deferred payment plan, an installment plan with a down payment, a rent to own plan) The expression for the amount of Harold’s last payment is (x-100y, 100y-x, x-100+y, x+100-y)
Mathematics
1 answer:
ZanzabumX [31]2 years ago
5 0

Answer:

the healer gave Harold a deferred payment plan. The expression for the amount of Harold’s last payment is x - 100y

Step-by-step explanation:

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The equation of the piecewise function f(x) is below. What is the value of f(3)?
JulijaS [17]

Option B: 5 is the value of f(3)

Explanation:

The equation of the piecewise function is given by

f(x)=\left\{\begin{aligned}-x^{2}, & x

We need to find the value of f(3)

The value of the function f can be determined when x=3 by identifying in which interval does the value of x=3 lie in the piecewise function.

Thus, x=3 lies in the interval x\geq 0 , the function f is given by

f(x)=x+2

Substituting x=3 in the function f(x)=x+2, we get,

f(3)=3+2

f(3)=5

Thus, the value of f(3) is 5.

Therefore, Option B is the correct answer.

8 0
3 years ago
Can anyone help me please
Andrew [12]

I think the answer is #4

4 0
2 years ago
Find the perimeter of the figure below, in feet.
Sergeu [11.5K]

Answer:

add all and multiply it by 2

Step-by-step explanation:

i don't kniw

3 0
3 years ago
WILL GIVE BRAINLIEST AND THANKS AND RATING!
Lorico [155]
8 is 6.2
9 is 7
The pattern here is +0.8.
4.6 - 3.8=0.8
5.4-4.6=0.8, and so on
6 0
3 years ago
In 1960, the population of a town was 14 thousand people. Over the course of the next 50 years, the town grew at a rate of 30 pe
andre [41]

SOLUTIONS

Given: Assume y is the population

\begin{gathered} t=0=1960,y=14030 \\ t=1=1961,y=14060 \\ so\text{ b = 14000} \\ so\text{ k = 30} \end{gathered}

The town grow at the rate of 30 people per year.

y=kt+14000y=30t+14000

(A) The population predicted to be in 2030 will be

\begin{gathered} 2030-1960=70 \\ y=30k+14000 \\ y=30(70)+14000 \\ y=2100+14000 \\ y=16100people \end{gathered}

(B) so when y = 15000, find t

\begin{gathered} y=15000 \\ y=30t+14000 \\ 15000=30t+14000 \\ 15000-14000=30t \\ 1000=30t \\ t=\frac{1000}{30} \\ t\approx33 \\ t=1960+33 \\ t=1993 \end{gathered}

3 0
11 months ago
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