<h3>Given</h3>
tan(x)²·sin(x) = tan(x)²
<h3>Find</h3>
x on the interval [0, 2π)
<h3>Solution</h3>
Subtract the right side and factor. Then make use of the zero-product rule.
... tan(x)²·sin(x) -tan(x)² = 0
... tan(x)²·(sin(x) -1) = 0
This is an indeterminate form at x = π/2 and undefined at x = 3π/2. We can resolve the indeterminate form by using an identity for tan(x)²:
... tan(x)² = sin(x)²/cos(x)² = sin(x)²/(1 -sin(x)²)
Then our equation becomes
... sin(x)²·(sin(x) -1)/((1 -sin(x))(1 +sin(x))) = 0
... -sin(x)²/(1 +sin(x)) = 0
Now, we know the only solutions are found where sin(x) = 0, at ...
... x ∈ {0, π}
Answer:
11%
Step-by-step explanation:
1. Fill out the table with the correct numbers.
2. After you fillout the numbers, you should notice that under the column car and in the first row, there should be the number 18.
3. We know the total number of students under the age of 15 is 165.
4. To find the percent:
18/165 * 100
= 11%
ticket sale on Saturday night is triple the ticket sale on Friday night.
Therefore
ticket sales on Saturday night = 3 x 12425 = 37275
Then
ticket sales for both nights = 12425 + 37275 = 49700
A ticket costs 35.
Let the number of people that attended the carnival on both nights be n.
Then, we have
Therefore 1420 people attended the carnival on both nights
Answer:
x is EQUIVALENT to 2.89
Step-by-step explanation:
