Answer:
yes it is
Step-by-step explanation:
Check the picture below.
you can pretty much count those lengths off the grid.
recall that A = 1/2 bh.
Given:
The sequence is 25, 20, 15, 10, 5.
To find:
The ninth term of the given sequence.
Solution:
We have,
25, 20, 15, 10, 5
It is an AP because the difference between two consecutive terms are same.
Here,
First term (a) = 25
Common difference (d) = 20-25
= -5
The nth terms of an AP is
Where, a is the first term and d is the common difference.
Putting a=25, n=9 and d=-5 to get the 9th term.
Therefore, the ninth term of the given sequence is -15.
The answer is B.
The only reason it will be 200 is because the numbers 1,2,3,4,5,and 6 are all an option so the probability of 5 is 1/6 and if you multiply 1/6 by 1,200 you will get 200. Hope this helped!
I don't know what the relation in your problem is, but I'll just explain this using my own example.
Let's use the following relation as the example (pretend it's a table of values):
x | y
0 | 1
2 | 4
4 | 7
6 | 10
To write the relation as ordered pairs, you need the x and y values from the table. An ordered pair is written like this: (x,y).
Based off of this explanation, the ordered pairs from this example would be:
(0,1) (2,4) (4,7) (6,10)