H +t = 8
$6h + $7t ≤$50
h+t = 8
h +t-t=8-t
h= 8-t
$6(8-t) + $7t ≤$50
48-6t +7t≤50
48-48+t≤50-48
t ≤ 2
h=6
$6(6) + $7(2) ≤$50
36 + 14 ≤ 50
50≤50
He can buy 6 pounds of ham and 2 pounds of turkey
(-8)/(2y-8)=(5/(y+4))-7y+(8/(y^2-16))
(-4)/(y-4)=(5/(y+4))-7y+(8/(y+4)(y-4))
((-4)(y+4))/((y+4)(y-4))=((5(y-4))/(y+4)(y-4))-(7y(y+4)(y-4))/(y+4)(y-4))+(8/(y+4)(y-4))
(-4(y+4))=(5(y-4))-(7y(y+4)(y-4))+8
-4y-16=5y-20-(7y(y^2-16))+8
-4y-16=5y-20-7y^3+112y+8
-4y-16=117y-7y^3-12
-4=(121-7y^2)(y)
None of these choices would be equal to -4
For this case we must find the value of n of the following equation:

Taking common factor "n" from the left side of the equation we have:

Multiplying by 5 on both sides of the equation:

Dividing between 6 on both sides of the equation:

Thus, the value of n is 20.
Answer:
