Answer: The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.
Step-by-step explanation:
Let x and y area the random variable that represents the heights of women and men.
Given : The heights of women aged 20 to 29 are approximately Normal with mean 64 inches and standard deviation 2.7 inches.
i.e.

Since , 
Then, z-score corresponds to a woman 6 feet tall (i.e. x=72 inches).
[∵ 1 foot = 12 inches , 6 feet = 6(12)=72 inches]

Men the same age have mean height 69.3 inches with standard deviation 2.8 inches.
i.e.

Then, z-score corresponds to a man 5'10" tall (i.e. y =70 inches).
[∵ 1 foot = 12 inches , 5 feet 10 inches= 5(12)+10=70 inches]

∴ The z-scores for a woman 6 feet tall is 2.96 and the z-scores for a a man 5'10" tall is 0.25.
Answer:
t=382
Step-by-step explanation:
Answer:
sample 1: 75
sample 2: 86
Step-by-step explanation:
15. 16 yards. Add side a (2 yds.) and b (6 yds.), divide by 2 and then multiply by the height (4 yds.)
16. I believe it would be 48 m. find the area of each rectangle and then add it. (6x2)+(12x3) -> 12+36= 48 square meters.
Hope it helps! -cat
We can create a formula first.
X will be the unknown number
840= 357+x
-357 -357
483 = x
Hope this helps