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AnnyKZ [126]
3 years ago
15

What is this question called?

Mathematics
2 answers:
Papessa [141]3 years ago
7 0

Answer:

Step-by-step explanation:

a proportion.  Both ratios are the same thing. If you divide 15000 by 30 you get 500

If you divide 210 by 30, you get 7

It is always true that a proportion will have equal equal ratios on either side of the equal sign.

frez [133]3 years ago
6 0

Answer:

It should be Ratio and Proportions .

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-1/3 = r -3/4 what is r?
Rus_ich [418]

Answer:

5/12 = r

Step-by-step explanation:

-1/3 = r - 3/4

+3/4     +3/4

5/12 = r

5 0
3 years ago
Solve system equation Substitution method <br> 4+t=-8
Dima020 [189]

Answer:

T=-12

Step-by-step explanation:

Isolate variable by subtracting 4 on both sides

t=-12

5 0
3 years ago
Read 2 more answers
I.
Kaylis [27]
It’s A because (-2)2+(4)2-2(-2)+4(4)+8=0
-4+8+4+-16+8
(8+8) (-4+4) (-16)
16 -16 =0
4 0
3 years ago
How much time will it take for a bug to travel 75 meters across the floor if it is traveling at 5 m/s?
Karolina [17]
15 seconds, I did this in class and I got most of them right and the ones I didn’t get right were way harder than that
4 0
3 years ago
Suppose that the number of asbestos particles in a sample of 1 squared centimeter of dust is a Poisson random variable with a me
Maslowich

Answer:

The approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357

Step-by-step explanation:

For a sample of 10 sqaured centimeters of dust, the total amount of asbestos particles has a Poisson distribution with a mean of 1000/1 * 10 = 10000.

We will approximate this probability to a normal distribution. The variance is also 10000 (because it is poisson), therefore the standard deviation is √10000 = 100. Lets call X the distribution, and W its standarization, given by

W = \frac{X-\mu}{\sigma} = \frac{X-10000}{100}

We have

P(X>10110) = P(\frac{X-10000}{100} > \frac{10110-10000}{100}) = P(W > 1,1) = 1-\phi(1,1) = 1-0.8643 = 0.1357

Where \phi is the cummulative distribution function of a standard normal distribution. The values of \phi are well known and they can be found in the attached file.

We conclude that the approximate probability that 10 squared centimeters of dust contains more than 10110 particles is 0.1357.

Download pdf
4 0
3 years ago
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