The value of the given expression after addition is 199 and this can not written as a mixed number in the simplest form.
According to the question,
We have the following expression:
212+(-13)
Now, we know that the multiplication of one negative and one positive integers is always positive.
So, we have the following expression:
212-13
199
Now, this number is whole number and it can not be written as a mixed number. It could only have been written as a mixed number when the result would have been in a fraction.
Hence, the value of the given expression after addition is 199 and this can not written as a mixed number in the simplest form.
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Answer:
Area of the rhombus will be a repeating decimal.
Step-by-step explanation:
In a terminating decimals, numbers get terminated after decimal like
1/4 = 0.25
while in repeating decimals, numbers get repeated after decimal like
1/3 = 0.33333
When we multiply two decimals which are repeating and terminating decimals the result will be a repeating decimal.
Therefore area of the rhombus will be a repeating decimal.
Answer:
x = a(c - b)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Step-by-step explanation:
<u>Step 1: Define Equation</u>
x/a + b = c
<u>Step 2: Solve for </u><em><u>x</u></em>
- Subtract <em>b</em> on both sides: x/a = c - b
- Multiply <em>a</em> on both sides: x = a(c - b)
