To get the probability of two individual events both occurring,
you have to multiply the probabilities of their individual events occurring. Therefore
in this problem, the probability that a student selected at random will pass
both French 101 and French 102 is 0.683 (.75 x .91). The answer is already
rounded to three decimal places.
Answer:
about $66.68
Step-by-step explanation:
please give brainliest
Answer:
it is a function
Step-by-step explanation:
Answer:
h
Step-by-step explanation:
multiplication and inference
Answer: (60/13, 6/13)
Concept:
There are three general ways to solve systems of equations:
- Elimination
- Substitution
- Graphing
Here, we are going to use <u>elimination </u>since all the variables are in the corresponding position.
Solve:
<u>Given</u>
![\left \{ {{2x+7y=-6} \atop {4x - y=18}} \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7B2x%2B7y%3D-6%7D%20%5Catop%20%7B4x%20-%20y%3D18%7D%7D%20%5Cright.)
<u>Multiply the first equation in order to eliminate [x]</u>
![\left \{ {{4x + 14y = -12} \atop {4x - y = 18}} \right.](https://tex.z-dn.net/?f=%5Cleft%20%5C%7B%20%7B%7B4x%20%2B%2014y%20%3D%20-12%7D%20%5Catop%20%7B4x%20-%20y%20%3D%2018%7D%7D%20%5Cright.)
<u>Subtract the second equation from the first equation to eliminate [x]</u>
![14y-y=-12+18](https://tex.z-dn.net/?f=14y-y%3D-12%2B18)
![13y=6](https://tex.z-dn.net/?f=13y%3D6)
<u>Divide 13 on both sides</u>
![13y/13=6/13](https://tex.z-dn.net/?f=13y%2F13%3D6%2F13)
![\boxed{y=\frac{6}{13} }](https://tex.z-dn.net/?f=%5Cboxed%7By%3D%5Cfrac%7B6%7D%7B13%7D%20%7D)
<u>Substitute [y] value in order to get [x] value</u>
4x - y = 18
4x - 6/13 = 18
4x = 18 + 6/13
4x = 240/13
![\boxed{x=\frac{60}{13} }](https://tex.z-dn.net/?f=%5Cboxed%7Bx%3D%5Cfrac%7B60%7D%7B13%7D%20%7D)
Hope this helps!! :)
Please let me know if you have any questions