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Elenna [48]
3 years ago
9

100 cm3 of the copper sulfate solution contains 1.8 g of copper sulfate.

Chemistry
1 answer:
elixir [45]3 years ago
8 0

Answer:

The mass of copper sulfate in 25 cm³ of the copper sulfate solution is 0.45 g

Explanation:

The given parameters are;

The volume of the copper sulfate solution = 100 cm³

The mass of the copper sulfate in the solution = 1.8 g

Therefore, the mass of copper sulfate in 25 cm³ of the solution is given as follows;

The mass of copper sulfate in 100 cm³ of the solution = 1.8 g

The mass of copper sulfate in 1 cm³ of the solution  = 1.8 g/100 = 0.018 g

Therefore;

The mass of copper sulfate in 25 × 1 = 25 cm³ of the solution, m  = 25×0.018 g = 0.45 g

∴ The mass of copper sulfate in 25 cm³ of the solution, m = 0.45 g

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Explanation:

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3 years ago
How are selective breeding, cloning, and genetic engineering similar? They are all controlled by nature. They are all controlled
sveticcg [70]

Answer:They are all controlled by the human beings.

Explanation:

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7 0
4 years ago
Read 2 more answers
Chlorine gas is added to a large flask to a pressure of 1.85 atm, at a temperature of 322 K. Phosphorus is added, and a reaction
AVprozaik [17]

Answer:

The volume of the flask is<u> 20.245 litres .</u>

Explanation:

We are given with following information-

PV=nRT -------- 1

where R =0.0821L.atom/mole.K

Molar mass of PCl_5=208.22g/mole

The given chemical equation is -

2P _(_s_)+5Cl_2 _(_g_)\rightarrow2PCl_5  _(_s_) --------- 2

Now , calculation -

Mass of PCl_5 formed = 118g

Molar mass of PCl_5 = 208.22g/mole

      Mole = \frac{mass (g)}{molar mass}

Therefore , moles of PCl_5 formed = \frac{118}{208.22}

     From equation 2 , we get to know that ,

 2mole PCl_5 formed from 5 mole Cl_2 _(_g_)

Therefore , \frac{118}{208.22} mole PCl_5 formed from \frac{5}{2} \times\frac{118}{208.22} mole Cl_2 _(_g_)

Moles of Cl_2 _(_g_) used =\frac{5\times118}{2\times208.22} mole

R= 0.0821L.atom/mole.K

Pressure (P)= 1.85atm

Temperature (T)= 322K

Moles of  Cl_2 _(_g_) (n)= \frac{5}{2} \times\frac{118}{208.22} moles

Applying  the formula above in 1 equation , that is

PV = nRT

putting the given values -

1.85 \times V=\frac{5}{2} \times\frac{118}{208.22}\times0.0821\times322

 V = 20.245 litres.

Hence , the volume of the flask is <u>20.245 litres . </u>

 

8 0
3 years ago
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Explanation:

5 0
3 years ago
34 grams of chlorine gas react with sodium to form how many grams of sodium chloride? 2 na + cl2 --&gt; 2 nacl
mr Goodwill [35]
Hello!

The balanced chemical equation for the reaction between sodium and chlorine is the following:

2Na + Cl₂ → 2NaCl

To know the mass of Sodium Chloride produced, we are going to use the following conversion factor to go from grams of Chlorine gas to grams of Sodium Chloride:

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So, 56,007 g of NaCl are produced

Have a nice day!
5 0
3 years ago
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