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4 years ago

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Determine the number of valence electrons for magnesium

1 answer:

12345 [234]4 years ago

3 0

Answer:

Magnesium has 2 valence electrons.

Explanation:

The atomic number of magnesium is 12. This means that it has 12 protons and 12 electrons. The first electron shell can hold 2 electrons, the second can hold 8, so the third will have 2 electrons. The outermost shell of the atom has two electrons. Therefore, magnesium has 2 valence electrons.

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How many moles are in 1.5 x 10^20 molecules of NH3?

Keith_Richards [23]

<span>Because the question is asking moles of NH3, the compound, any subscripts are irrelevant. It only wants to know how many moles of NH3 molecules, not individual atoms.

Therefore, we can simply convert to moles. 1.5x10^23/6.022x10^23 = .249 moles of NH3.

(If it were to ask moles of Hydrogen, for example, you would multiply the answer by 3, because there are 3 atoms of Hydrogen per one molecule of NH3. But this only asks for moles of the entire compound).

hope you have a great day! :)
</span>

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4 years ago

[24 points] A sample of soil has a total volume of 205 cm3. The soil mass when saturated is 361 g. A specific yield test was con

telo118 [61]

Answer:

Follows are the solution to the given question:

Explanation:

Dry Soil weight = solid soil weight = $284 \ grams$

solid soil volume = $205 \ cc$

saturated mass soil = $361 \ g$

The weight of the soil after drainage is = $295 \ g$

Water weight for soil saturation = $(361-284) = 77 \ g$

Water volume required for soil saturation = $\frac{77}{1} = 77 \ cc$

Sample volume of water: $= \frac{\text{water density}}{\text{water density input}}$

$= 361- 295 \\\\ = 66 \ cc$

Soil water retained volume = (draining field weight - dry soil weight)

$= 295 - 284 \\\\ = 11 \ cc.$

$\text{POROSITY}= \frac{\text{Vehicle volume}}{\text{total volume Soil}}$

$= \frac{77}{(205 + 77)} \\\\= \frac{77}{(282)} \\\\ = 27.30 \%$

(Its saturated water volume is equal to the volume of voids)

$\text{YIELD SPECIFIC} = \frac{\text{Soil water volume}}{\text{Soil volume total}}$

$= \frac{66}{(205+77)}\\\\= \frac{66}{(282)}\\\\=0.2340\\\\ = 0.23$

$\text{Specific Retention}= \frac{\text{Volume of soil water}}{\text{Total soil volume}}$

$= \frac{11}{282} \\\\= 0.0390 \\\\ = 0.04$

6 0

3 years ago

Predict the products of below reaction, and whether the solution at equilibrium will be acidic, basic, or neutral.

kati45 [8]

Answer: The product of the given reaction is $HNO_{3}$ and the solution at equilibrium will be acidic.

Explanation:

When two or more chemical substances react together then it forms new substances and these new substances are called products.

For example, $3N_{2}O_{5} + 3H_{2}O \rightarrow 6HNO_{3}$

This shows that nitric acid $(HNO_{3})$ is the product formed and it is an acidic substance.

Hence, the solution at equilibrium will be acidic in nature.

Thus, we can conclude that the product of the given reaction is $HNO_{3}$ and the solution at equilibrium will be acidic.

8 0

3 years ago

How many atoms of carbon are in the sample

Serhud [2]

There are six atoms in the carbon

6 0

3 years ago

If I mix bleach and namona and throw it on a person what will happen

satela [25.4K]

Answer:

They have the chance to inhale toxic fumes secreted by the mixture.

Explanation:

7 0

3 years ago