Question

Approximately how many moles of chlorine make up 1.79 × 1023 atoms of chlorine?

Answer 1

Answer:

There are 0.2972 moles of chlorine in $1.79\times 10^{23}$ atoms of chlorine.

Explanation:

$N=n\times N_A$

Where:

N = Number of particles / atoms/ molecules

n = Number of moles

$N_A=6.022\times 10^{23} mol^{-1}$ = Avogadro's number

We have:

N = $1.79\times 10^{23}$  atoms of chlorine

n =?

$n=\frac{N}{N_A}=\frac{1.79\times 10^{23}}{6.022\times 10^{23} mol^{-1}}$

n = 0.2972  moles

There are 0.2972 moles of chlorine in $1.79\times 10^{23}$ atoms of chlorine.

Answer 2

Answer:

0.297mol Cl

Step-by-step explanation:

To convert from atoms to moles we must divide the amount of moles by Avagadro’s number.

1.79 x 10^23 atoms / 6.02 x 10^23
= 0.297mol Cl