Answer : The correct option is, (2) Cr (Chromium)
Explanation :
The reactivity series of metal are arranged of the reactivity from the highest to the lowest. Reactivity series is used to determine the products of the single displacement reactions. In the single displacement reaction, the most reactive metal displaces the least reactive metal.
From the given reactivity series we conclude that there are two metal (Mg and Cr) are more reactive metal than the Ni and there are two metal (Pb and Cr) are less reactive metal than the Zn. So, the Cr (Chromium) is the metal which is more active than Ni and less active than Zn.
Hence, the correct option is, (2) Cr
From the ones that you are showing me <span>the more positive the potential the more likely: </span>
<span>Fe+3 + e- ---> Fe+2
I hope this is something very useful</span>
Answer:
it's easier to lose one electron because it's less work for the atom to do and easier to lose one than gain a whole 7, because the atom wants to gain a full outer shell as soon as possible
Answer:
That leaves us with: 1s2 2s2 2p6 And that is the electron configuration for F- , the Fluoride ion.
Explanation:
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