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aivan3 [116]
4 years ago
10

Which half-reaction is most easily oxidized?

Chemistry
2 answers:
netineya [11]4 years ago
7 0
From the ones that you are showing me <span>the more positive the potential the more likely: </span>

<span>Fe+3 + e- ---> Fe+2
I hope this is something very useful</span>
Alenkasestr [34]4 years ago
7 0

the right answer is d. Na+ + e- Na = -2.71 V

i think, i had trouble finding this one...

posting this for future users!

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How are valance electrons related to nuclear reactions?
Harrizon [31]

Explanation:

Valence electrons are not related in anyways to nuclear reactions.

They do not take part in nuclear reactions. Only some inner orbital electrons have the tendency of taking part in nuclear reactions.

The valence electrons are the outermost electrons in an atom.

Nuclear reactions takes place in the nucleus of an atom.

Valence electrons are exchanged and shared for chemical reactions to take place in between atoms.

We can conclude that valence electrons have no relevance in nuclear reactions

learn more:

Chemical reactions brainly.com/question/3953793

#learnwithBrainly

6 0
3 years ago
Thermal energy is a form of
Mrrafil [7]

Thermal energy is an example of kinetic energy, as it is due to the motion of particles, with motion being the key. Thermal energy results in an object or a system having a temperature that can be measured. Thermal energy can be transferred from one object or system to another in the form of  heat.                hope this helps

8 0
4 years ago
Read 2 more answers
If you have 2 Moles of C3H6 and 10 Moles of O2, which reactant is limiting the following reaction: 2C3H6 + 9O2 → 6CO2 + 6H2O?
Hatshy [7]

Answer:

The limiting reactant is propene, C_3H_6.

Explanation:

2C_3H_6 + 9O_2 \rightarrow 6CO_2 + 6H_2O

Moles of nitrogen propene  = 2 mol

Moles of oxygen  = 10 mol

According to reaction, 2 moles of propene reacts with 9 moles of oxygen gas, then 2 moles of propene will react with:

=\frac{9}{2}\times 2mol=9\text{mol of oxygen gas}

According to the question, we have 10 moles of oxygen gas, which is more than 9 moles of oxygen gas. This indicates that propene is present in a limiting amount hence, it is a limiting reactant.

The limiting reactant is propene, hence the correct answer is the C_3H_6.

5 0
3 years ago
A sample of an unknown substance has a mass of 0.158 kg. If 2,510.0 J of heat is required to heat the substance from 32.0°C to 6
blondinia [14]
Specific heat is the amount of heat absorb or released by a substance to change the temperature to one degree Celsius. To determine the specific heat, we use the expression for the heat absorbed by the system. Heat gained or absorbed in a system can be calculated by multiplying the given mass to the specific heat capacity of the substance and the temperature difference. It is expressed as follows:

Heat = mC(T2-T1)

By substituting the given values, we can calculate for C which is the specific heat of the material.

2510 J = .158 kg ( 1000 g / 1 kg) (C) ( 61.0 - 32.0 °C)
C = 0.5478 J / g °C
6 0
3 years ago
I NEED HELP PLEASE, THANKS!
ira [324]

Answer:

About 0.652

Explanation:

Because the reaction is balanced, we can go straight to the next step. The molar mass of potassium is about 39.098, while the molar mass of hydrogen gas is 2 and the molar mass of water is 18. Therefore, 25.5g of potassium would be about 0.652 moles, and 220 grams of water would be about 12.222 moles, making potassium the limiting reactant. Since there is a single unit of each compound on both sides of the equation, there would be an equal amount of moles of potassium and hydrogen, and therefore about 0.652 moles of hydrogen gas would be produced. Hope this helps!

6 0
3 years ago
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