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8_murik_8 [283]
2 years ago
9

Eric is told by his doctor that he needs to lose 15 pounds. If Eric now weights 285 pounds,then by what percentage should Eric w

eight decrease?
Mathematics
1 answer:
tatuchka [14]2 years ago
3 0

Answer:

5.26%

Step-by-step explanation:

15/285=x/100. 15 is the amount of weight he wants to lose. x=5.26%

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4(10b-4) <br><br> Explain please
Angelina_Jolie [31]
<h3>Answer:   40b - 16</h3>

Work Shown:

4(10b-4)

4*10b - 4*4

40b - 16

I multiplied the outer term 4 by each term inside. Refer to the distribution property (aka distributive property).

4 0
2 years ago
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The painting shown on the right has an area of 300 in^2. what is the value of x?
Nataly [62]

Answer: X = 10.20240940...

Step-by-step explanation:

x(2x + 9) = 2x^2 + 9x

2x^2 + 9x = 300

- 300 ON BOTH SIDES

2x^2 + 9x - 300 = 0

SOLVE USING THE QUADRATIC FORMULA

x = -b +/- all root (b)^2 - 4(a)(c) All over 2(a)

When all the values are plugged in:

When using "+" in the equation you should get:

x = 10.20240940…

When using "-" in the equation you should get:

x = −14.70240940…

Now.. you CANNOT have a negative length, so you cross of the negative value leaving you one value for x which is 10.20240940...

YOUR ANSWER IS:    x   =  10.20240940...

4 0
2 years ago
, use a number line. Start at 0. Move forward 5 and then back up 7. How many yards must he get to get back to 0?
krek1111 [17]

Answer:

2 yards.

Step-by-step explanation:

If you do what was stated in the problem, you would be left at -2. So, you would need to move up 2 yards to get back to 0.

8 0
2 years ago
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Find the probability of picking 4 consonant and 1 vowels when 5 letters are picked (without replacement) from a set of alphabet
Ganezh [65]

The required probability is 0.45

We have total 26 letters in english, of which 21 are consonants and 5 are vowels.

According to the question, we have to select 5 of them of which 4 will be consonants and 1 will be vowel.

Suppose we want to have the vowel in the first selection, so the probability of picking a vowel is equal to the quotient between the number of vowels and the number of total number of letters.

So the probability is 5/26

Now, a letter has been selected, so in the set, we have 25 letters left.

In the next 4 selections, we must select consonants.

In the second selection the probability is 21/25

In the third selection the probability is 20/24

In the fourth selection the probability is 19/23

In the last selection the probability is 18/22

So, the probability is (5/26)×(21/25)×(20/24)×(19/23)×(18/22)

Now, remember that we take that the vowel must be in the first place, but it can be in any five places, so if we add the permutations of the vowel letter we have,

P = 5×(5/26)×(21/25)×(20/24)×(19/23)×(18/22) = 0.45

Learn more about probability here :

brainly.com/question/251701

#SPJ10

5 0
1 year ago
-2 (m+n-4)+5 (-2m+2n)+n (m+4n-5)
Natalka [10]
So if you want to add
we distribute
a(b+c)=ab+ac so
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5(-2m+2n)=-10m+10n

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so total we ahve
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add like temrs
4n^2-12m+3n+mn+8
5 0
3 years ago
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