Answer:
on the job training
Explanation:
I would personally suggest on the job training. This is because it provides the new candidates specific experience on how the job will be on a day-to-day basis. This can drastically increase the performance of hired candidates since they will know exactly what and how to perform for that exact company. Also, it will help the candidates get acquainted with the other current employees and even get rid of candidates who would have eventually quit by showing them exactly what the job will be like. Some candidates will realize that the job is not right for them and simply give up and quit.
Answer:
Let f be a function
a) f(n) = n²
b) f(n) = n/2
c) f(n) = 0
Explanation:
a) f(n) = n²
This function is one-to-one function because the square of two different or distinct natural numbers cannot be equal.
Let a and b are two elements both belong to N i.e. a ∈ N and b ∈ N. Then:
f(a) = f(b) ⇒ a² = b² ⇒ a = b
The function f(n)= n² is not an onto function because not every natural number is a square of a natural number. This means that there is no other natural number that can be squared to result in that natural number. For example 2 is a natural numbers but not a perfect square and also 24 is a natural number but not a perfect square.
b) f(n) = n/2
The above function example is an onto function because every natural number, lets say n is a natural number that belongs to N, is the image of 2n. For example:
f(2n) = [2n/2] = n
The above function is not one-to-one function because there are certain different natural numbers that have the same value or image. For example:
When the value of n=1, then
n/2 = [1/2] = [0.5] = 1
When the value of n=2 then
n/2 = [2/2] = [1] = 1
c) f(n) = 0
The above function is neither one-to-one nor onto. In order to depict that a function is not one-to-one there should be two elements in N having same image and the above example is not one to one because every integer has the same image. The above function example is also not an onto function because every positive integer is not an image of any natural number.
Answer:
string words[6];
words[0]="humming";
words[1]=words[0];
Explanation:
The above statement declares an array of size 6 which can store elements of type string or word. Then I have initialized the first and second elements with the word humming and the rest of the places in the arrays are uninitialized.
You have to include the header file string so that this array could work otherwise it will not.
