Answer:
D) is the correct answer in my opinion
Answer:
Explanation:
Preparation of competent cells -
Transformation
recovery
plating
The answers would be:
Genotype Phenotype
Tt Tall stemmed
tt Short stemmed
Genotypic ratio : 2:2 or 1:1
Phenotypic ratio: 2:2 or 1:1
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<u>You can read on to see how this was done:</u>
Tall stems (T) are dominant to short stems (t).
First figure out the genotypes of the parents. We have a short-stemmed plant and a heterozygous long-stemmed plant cross.
For short stem to occur, you need 2 pairs of short alleles. So the first parent would have a genotype of tt.
Heterozygous long-stemmed means that the parent has one of each allele. So the genotype of the second parent would be, Tt.
Now we can make our Punnett Square.
tt x Tt
<u> t t </u>
<u>T | Tt | Tt</u>
<u>t | tt | tt</u>
Let's list down the genotypes and phenotypic results.
Genotype no. Phenotype
Tt 2 Tall stemmed
tt 2 Short stemmed
So from that we can answer the other questions:
Genotypic ratio : 2:2 or 1:1
Phenotypic ratio: 2:2 or 1:1
Answer:
The correct answer is -
exposure of the opposite environments to the species and see if they are able to be active in cold waters.
If they are then species of organism in Maine and could have more ice-nucleating agents which are responsible for their high ability for activity in cold waters.
Explanation:
To test the assess if the Maine species of organisms are especially able to be active in cold waters an experiment can be designed where one needs to place the species or animals from Maine and Bahamas in reverse conditions.
Maine animals are placed in warm water environments and species from the Bahamas can be placed in cold water. Finding if they are able to adapt in reverse condition by calculating various processes and motion, if yes then it shows that it is not a special ability to survive in cold temps. However, if it is not then the Maine poikilotherms are specially designed for their environment. In case of yes then species of organism in Maine and could have more ice-nucleating agents
7 g of dietary fat in each 22.7 g piece.
To convert pounds to kilograms,
1 kg = 2.205 lbs
Thus; 1 lb is equal to 1/2.205 kg
Thus; (1/2.205) × (7/22.7)
= 0.14 kg
Therefore; that would be 0.14 kg of fat per 1 lb of chocolate.
