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Lemur [1.5K]
3 years ago
9

BD bisects LABC. Find the value of x

Mathematics
2 answers:
navik [9.2K]3 years ago
6 0
X = 3, hopefully this helps you, have a great day ! >33
Over [174]3 years ago
3 0

Answer:

x = 3

Step-by-step explanation:

8x + 3 = 9x

3 = x

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I need help on this question
astraxan [27]

Answer:

uhh

Step-by-step explanation:

8 0
2 years ago
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Assume that the random variable X is normally distributed with mean u = 45 and standard deviation o = 14.
larisa86 [58]

Answer:

P(57 < X < 69) = 0.1513

Step-by-step explanation:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

\mu = 45, \sigma = 14

Find P(57 < X < 69):

This is the pvalue of Z when X = 69 subtracted by the pvalue of Z when X = 57. So

X = 69

Z = \frac{X - \mu}{\sigma}

Z = \frac{69 - 45}{14}

Z = 1.71

Z = 1.71 has a pvalue of 0.9564

X = 57

Z = \frac{X - \mu}{\sigma}

Z = \frac{57 - 45}{14}

Z = 0.86

Z = 0.86 has a pvalue of 0.8051

0.9564 - 0.8051 = 0.1513

P(57 < X < 69) = 0.1513

4 0
3 years ago
Helpppp me please!! I dont understand.
Andrei [34K]

Answer:

A) mPQ = 71º

B) mSR = 161º

C) mQRT = 199ª

D) mPSR = 270º

E) mPS = 109º

Step-by-step explanation:

We know that mST is 19º and QR is also 19º because they're opposite angles. We also know that angle PUR is 90º.

If we subtract 19º from 90º we get 71º for mPQ.

We also know that TR is a 180º angle. Using this if we take 19º from 180º we're left with 161º for mSR.

Using the 180º from angle TR, as well as the 19º from mQR we know that mQRT has to be 199º.

A circle is 360º and a right angle is 90º. That means that mPSR is 270º.

Knowing that TR is 180º and that PR is 90º, PTº must be supplementary making it also 90º. Adding the 19º from ST to the 90º from TP we know that PS is 109º

4 0
2 years ago
Can someone please help me with this question?
ryzh [129]

Answer: (3,2)

Step-by-step explanation:

4 0
3 years ago
How do i graph <br> y=-3/4x-1
Tasya [4]

Answer:

Start at -1 and go down 3 right 4,repeat. Then up 3 left 4 from -1, repeat.

Step-by-step explanation:

6 0
2 years ago
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