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3 years ago

BD bisects LABC. Find the value of x

Mathematics

2 answers:

navik [9.2K]3 years ago

6 0

X = 3, hopefully this helps you, have a great day ! >33

Over [174]3 years ago

3 0

Answer:

x = 3

Step-by-step explanation:

8x + 3 = 9x

3 = x

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natima [27]

7 , it’s x = 12 1/3, or in decimal form, 12.33. And at 8, it’s x = -6/11, or in decimal form, -0.54

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2 years ago

Find the slope of the line that passes through (-49, 68) and (-43, 67).

Arte-miy333 [17]

Answer:

Slope = 67 - 68 / -43 + 49

= -1 / 6

= - 1/6

Hope this helps

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3 years ago

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Ilia_Sergeevich [38]

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2 years ago

Read 2 more answers

Choose the function whose graph is given below.

torisob [31]

Answer:

A y=tanx

Step-by-step explanation:

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1 year ago

If g (x) = 1/x then [g (x+h) - g (x)] /h

lys-0071 [83]

Answer:

$\dfrac{-1}{x(x+h)}, h\ne 0$

Step-by-step explanation:

If $g(x) = \dfrac{1}{x}$ , then $g(x+h) = \dfrac{1}{x+h}$ . It follows that

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \cdot [g(x+h) - g(x)] \\&= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\end{aligned}$

Technically we are done, but some more simplification can be made. We can get a common denominator between 1/(x+h) and 1/x.

$\begin{aligned} \\\frac{g(x+h)-g(x)}{h} &= \frac{1}{h} \left( \frac{1}{x+h} - \frac{1}{x} \right)\\&=\frac{1}{h} \left(\frac{x}{x(x+h)} - \frac{x+h}{x(x+h)} \right) \\ &=\frac{1}{h} \left(\frac{x-(x+h)}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{x-x-h}{x(x+h)}\right) \\ &=\frac{1}{h} \left(\frac{-h}{x(x+h)}\right) \end{aligned}$

Now we can cancel the h in the numerator and denominator under the assumption that h is not 0.

$= \dfrac{-1}{x(x+h)}, h\ne 0$

5 0

3 years ago